我想将 xml 文件中的数据部分显示为 listview 一个 listview(winapp)。欢迎任何想法。提前致谢!
这是我的示例 xml 文件:
<xml xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882"
xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882"
xmlns:rs="urn:schemas-microsoft-com:rowset"
xmlns:z="#RowsetSchema">
<s:Schema id="RowsetSchema">
<s:ElementType name="row" content="eltOnly" rs:updatable="true">
<s:AttributeType name="ShipperID" rs:number="1"
rs:basetable="shippers" rs:basecolumn="ShipperID"
rs:keycolumn="true">
<s:datatype dt:type="int" dt:maxLength="4" rs:precision="10"
rs:fixedlength="true" rs:maybenull="false"/>
</s:AttributeType>
<s:AttributeType name="CompanyName" rs:number="2"
rs:nullable="true" rs:write="true" rs:basetable="shippers"
rs:basecolumn="CompanyName">
<s:datatype dt:type="string" dt:maxLength="40" />
</s:AttributeType>
<s:AttributeType name="Phone" rs:number="3" rs:nullable="true"
rs:write="true" rs:basetable="shippers"
rs:basecolumn="Phone">
<s:datatype dt:type="string" dt:maxLength="24"/>
</s:AttributeType>
<s:extends type="rs:rowbase"/>
</s:ElementType>
</s:Schema>
<rs:data>
<z:row ShipperID="1" CompanyName="Speedy Express"
Phone="(503) 555-9831"/>
<z:row ShipperID="2" CompanyName="United Package"
Phone="(503) 555-3199"/>
<z:row ShipperID="3" CompanyName="Federal Shipping"
Phone="(503) 555-9931"/>
</rs:data>
</xml>
结果应该是:
ShipperID CompanyName Phone
--------- -------------- --------------
1 Speedy Express (503) 555-9831
2 United Package (503) 555-3199
3 Federal Shipping (503) 555-9931