我在 Graph API 中有一条路径,我想将其转换为 FQL 查询。有没有可能只用一个查询来处理它?
me?fields=
photos.limit(1500).fields
(
name,
created_time,
source,
from,
likes.limit(1500)
),
albums.limit(1500).fields
(
photos.limit(1500).fields
(
name,
source,
likes
),
name,
likes.limit(1500),
place,
description,
updated_time,
cover_photo,
from
)