2

给定以下代码:

class testurl
{
    public void test()
    {
        try {
            URL url1 = new URL("file:../../foo/bar/");
            URL url2 = new URL(url1, "file.txt");

            URL url3 = new URL("file:../../../../foo/bar/");
            URL url4 = new URL(url3, "file.txt");

            URL url5 = new URL("file:../../../../../foo/bar/");
            URL url6 = new URL(url5, "file.txt");

            System.out.println("url1: " + url1.toString());
            System.out.println("url2: " + url2.toString());
            System.out.println("url3: " + url3.toString());
            System.out.println("url4: " + url4.toString());
            System.out.println("url5: " + url5.toString());
            System.out.println("url6: " + url6.toString());
        }
        catch (MalformedURLException ex) {
            System.out.println("MalformedURLException Exception:");
            System.out.println(ex);
        }
    }

    public static void main(String[] args)
    {
        testurl obj = new testurl();
        obj.test();
    }
}

我看到以下输出:

url1: file:../../foo/bar/
url2: file:../../foo/bar/file.txt
url3: file:../../../../foo/bar/
url4: file:../../foo/bar/file.txt
url5: file:../../../../../foo/bar/
url6: file:../foo/bar/file.txt

每当我使用“文件”协议在 URL 对象的路径中移动超过两 (2) 个“../”相对目录时,看起来 URL 类正在删除部分路径,当我使用

URL(URL, String)

构造函数,部分路径在构造过程中被删除。我尝试在文件之后使用“//” :在 URL 中,但它没有任何区别。

难道我做错了什么?或者这只是按设计工作?如果是这样,是否可以在不首先使用 URL 对象的getPathgetFile 方法对其进行解构的情况下附加/替换 URL 的文件部分?

这不是我使用的构造函数的设计目的吗?

我检查了 Java 跟踪:http ://docs.oracle.com/javase/tutorial/networking/urls/creatingUrls.html 它说:

You can create URL objects for these pages relative to their common base
URL:http://example.com/pages/ like this:

URL myURL = new URL("http://example.com/pages/");
URL page1URL = new URL(myURL, "page1.html");
URL page2URL = new URL(myURL, "page2.html");

所以看来我正在按预期使用它。

4

0 回答 0