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我制作了一个应用程序,它使用它service与服务器通信。来自服务的响应用于更新 UI。我习惯BroadcastReciever这样做。当我按下后退按钮时,服务继续在后台运行(我没有在主线程上运行服务)。现在后退按钮关闭我的应用程序。现在我想从服务向用户发送有关响应的通知。

有什么建议么?。

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1 回答 1

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通知:

  NotificationManager notificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);

                Notification.Builder builder = new Notification.Builder(
                        getApplicationContext());

                Intent intent = new Intent(getApplicationContext(),
                        YourActivity.class);
                intent.setAction("notification");
                PendingIntent pendingIntent = PendingIntent.getActivity(
                        getApplicationContext(), 0, i    intent,PendingIntent.FLAG_UPDATE_CURRENT | PendingIntent.FLAG_ONE_SHOT);

                builder.setSmallIcon(R.drawable.app_icon)
                        .setContentTitle("Next Appoinment....")
                        .setContentText(response)
                        .setTicker("Ticker")
                        .setLights(0xFFFF0000, 500, 500)
                        // setLights (int argb, int onMs, int offMs)
                        .setContentIntent(pendingIntent)
                        .setAutoCancel(true);

                Notification notification = builder.getNotification();
                notificationManager.notify(R.drawable.app_icon,
                        notification);
于 2013-07-11T12:33:51.267 回答