0

我得到这样的日期/时间格式来比较：

08:18:00 07/11/2013

7/11/2013 9:11:00 AM

如何将它们中的每一个转换为一种格式，以便我可以像这样编写 PHP 来找出哪个是较晚的日期/时间？

// $time1 will always be in HH:MM:SS MM/DD/YYYY format.
$time1 = "08:18:00 07/11/2013";

// $time2 will always be in MM/DD/YYYY HH:MM:SS format.
$time2 = "7/11/2013 9:11:00 AM";

$time_one = $mytimeconvertdate_time_first($time1);
$time_two = $mytimeconvertdate_date_first($time2);

if ($time_two > $time_one) {
   echo "time_two is later" . "\n";
}  else {
   echo "time_one is later" . "\n";
}

我试过这个，但第二个值不包含日期信息：

<?php
date_default_timezone_set('America/New_York');

// $time1 will always be in HH:MM:SS MM/DD/YYYY format.
$time1 = "08:18:00 07/11/2013";

// $time2 will always be in MM/DD/YYYY HH:MM:SS format.
$time2 = "7/11/2013 9:11:00 AM";

$dt1 = DateTime::createFromFormat("H:i:s m/d/Y", $time1);
$dt2 = DateTime::createFromFormat("m/d/Y H:i:s", $time2);
var_dump($dt1);
var_dump($dt2);
if ($dt1 < $dt2) echo "The first is earlier";

?>

输出是：

object(DateTime)#1 (3) {
  ["date"]=>
  string(19) "2013-07-11 08:18:00"
  ["timezone_type"]=>
  int(3)
  ["timezone"]=>
  string(16) "America/New_York"
}
bool(false)

更正为：

<?php
date_default_timezone_set('America/New_York');

// 注意：“一种是 24 小时制，另一种是 12 小时制，上午/下午。”

// $time1 will always be in HH:MM:SS MM/DD/YYYY format.
$time1 = "08:18:00 07/11/2013";

// $time2 will always be in MM/DD/YYYY HH:MM:SS format. 
$time2 = "7/11/2013 9:11:00 AM";

$dt1 = DateTime::createFromFormat("H:i:s m/d/Y", $time1);
$dt2 = DateTime::createFromFormat("m/d/Y g:i:s a", $time2);
var_dump($dt1);
var_dump($dt2);
if ($dt1 < $dt2) echo "The first is earlier" . "\n";

?>


object(DateTime)#1 (3) {
  ["date"]=>
  string(19) "2013-07-11 08:18:00"
  ["timezone_type"]=>
  int(3)
  ["timezone"]=>
  string(16) "America/New_York"
}
object(DateTime)#2 (3) {
  ["date"]=>
  string(19) "2013-07-11 09:11:00"
  ["timezone_type"]=>
  int(3)
  ["timezone"]=>
  string(16) "America/New_York"
}
The first is earlier
4

3 回答 3

3

用于从格式化文本DateTime::createFromFormat创建两个DateTime实例。然后，您可以直接比较实例以找出哪个时间较早。

$dt1 = DateTime::createFromFormat("H:i:s m/d/Y", $time1);
$dt2 = DateTime::createFromFormat("m/d/Y g:i:s a", $time2);

if ($dt1 < $dt2) echo "The first is earlier";
// etc
于 2013-07-11T10:28:41.800 回答
1

使用Carbon（这是 PHP 原生 DateTime 的 API），您可以简单地执行以下操作：

<?php
$time_one = Carbon::create(2013, 11, 7, 8, 18, 00); // 08:18:00 07/11/2013
$time_two = Carbon::create(2013, 11, 7, 9, 11, 00); // 7/11/2013 9:11:00 AM

if ($time_two->gt($time_one))
{
   echo "time_two is later\n";
}
else
{
   echo "time_one is later\n";
}


编辑：

当然，您不需要使用碳来达到预期的效果。但是请查看GitHub 上的 Carbon 源代码，了解它是如何完成的，您将通过一些示例了解如何实现您的目标。这只是善意的建议。

于 2013-07-11T10:36:44.457 回答
0

您可以执行以下操作：

$date1 = date("Y-m-d-H-i-s", strtotime("08:18:00 07/11/2013"));
$date2 = date("Y-m-d-H-i-s", strtotime("08:18:00 07/11/2013"));

if($date2 > $date1)
    ...
于 2013-07-11T10:27:37.593 回答