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我遇到了一次只能从 mysqli 打开一个结果集的问题。特别是，我试图在执行操作后循环选择查询并更新该查询中的列。

$db = new mysqli($DBServer, $DBUser, $DBPass , $DBName);
$sql = 'SELECT UPRN, POSTCODE FROM T_TEMP';
$stmt = $db->prepare($sql);
$stmt -> Execute();

<Create an array from the above select statement as i understand that mysqli can 
only hold one result set at once (seems odd). I am unsure how to do this such that
i can then reference UPRN and POSTCODE later>

$stmt->Close();

$sql = 'update T_TEMP set LAT = ?, LONG = ? where UPRN = ?';
$stmt = $db ->prepare($sql);  

<loop through that array built above grabbing UPRN and POSTCODE as you go through>

$postcode = urlencode(<Reference the postcode in the array>);
$request_url = "http://maps.googleapis.com/maps/api/geocode/xml?address=".$postcode."&sensor=false"; 
$xml = simplexml_load_file($request_url);

$lat = round(floatval($xml->result->geometry->location->lat),4);
$long = round(floatval($xml->result->geometry->location->lng),4);

$stmt -> bind_param('ddi',$lat,$long,$UPRN);

$stmt -> Execute();

<end loop>

我正在努力将第一个查询的结果放入一个数组中，然后在循环中引用该数组，以便我可以设置值。非常感谢任何帮助！

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2 回答 2

1

不要使用mysqli。请改用PDO。在后一种情况下，所需的代码将是一行：

include 'db.php';
$sql  = 'SELECT UPRN, POSTCODE FROM T_TEMP';
$stmt = $db->prepare($sql);
$stmt->execute();
$array = $stmt->fetchAll(); // here you are
于 2013-07-11T10:13:07.397 回答
-1

在被引导到正确的方向后，我结束了将结果集读入一个数组，然后循环遍历该数组。（此评论已被否决，但我正在对其进行编辑，以便其他人更容易找到）。

您不能打开两个 mysqli 查询，因为服务器只会让您在内存中保存一个（实际上是在服务器上）。因此，您将第一个查询读入 php 数组，然后在该数组中循环执行 mysqli 语句。

$vInteger =1; //This is just an example variable

$sql ='select column from table where column = ?'; //select with a passed value

$stmt = db->prepare($sql);

$stmt-> bind_param('i', $vInteger); //again, this could be a string, double or integer

$stmt->execute();

$result = $stmt->get_result(); //retrieves the results from the server into a class

while ($row = $result->fetch_assoc(){
   $Array[] = $row; //reads the rows into a new array
} 

$stmt -> free_result(); //Drop the mysqli bit cause you are going to need it again! :)

foreach($Array as $item){
  $item['Column']; // this is the column name from your original query


 // Of course in here you might want to do another mysqli query with the prepare etc etc and reference the $item.

 }

如果您决定使用对我有用的 mysqli，并且我认为 get_result 创建了一个 mysqli 结果类，您可以对其应用 fetch_assoc 方法。

于 2013-07-11T21:06:36.047 回答