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嗨，我已经为表 Persons 创建了一个存储过程，该表使用三个外键链接到这样的表地址：

-MaterialAddressID -HomeAddressID -PostalAddressID

这是我创建的存储过程：

-- =============================================
-- Author:  *******************
-- Create date: 11.07.2013
-- Description: Gets User Personal Details
-- =============================================
    ALTER PROCEDURE [eConnect].[GetUserPersonalDetails]
        @personId int
    AS
    BEGIN
        SELECT Persons.PersonalID,
               Persons.FirstName ,
               Persons.MiddleName , 
               Persons.LastName ,
               Persons.DateOfBirth,
               Persons.CityOfBirth ,
               Persons.BSN ,
               Persons.SecondaryEmail ,
               Persons.HomePhone ,
               Persons.WorkPhone ,
               Persons.MobilePhone,
               MaterialAddress.StreetName ,
               MaterialAddress.PostCode ,
               MaterialAddress.City ,
               HomeAddress.StreetName ,
               HomeAddress.PostCode ,
               HomeAddress.City ,
               PostalAddress.StreetName ,
               PostalAddress.PostCode ,
               PostalAddress.City
        FROM Sync_Persons as Persons
        JOIN Sync_Addresses as MaterialAddress ON Persons.MaterialAddressID = MaterialAddress.AddressID
        JOIN Sync_Addresses as HomeAddress ON Persons.HomeAddressID = HomeAddress.AddressID
        JOIN Sync_Addresses as PostalAddress ON Persons.PostalAddressId = PostalAddress.AddressID
        WHERE Persons.PersonalID = @personId
    END

当我尝试执行此操作时，出现此错误：

消息 245，级别 16，状态 1，过程 GetUserPersonalDetails，第 11 行将 varchar 值“I-024800”转换为数据类型 int 时转换失败。

在这种情况下，第 11 行是： -- 描述：获取用户个人详细信息

为什么我在评论中收到错误，我该如何更正？

4

1 回答 1

1

尝试更改此行 -

WHERE CAST(SUBSTRING(
     Persons.PersonalID, 
     CHARINDEX('-', Persons.PersonalID) + 1, 
     LEN(Persons.PersonalID)
) AS INT) = @personId

或试试这个 -

WHERE Persons.PersonalID = 'I-' + CAST(@personId AS VARCHAR(10))
于 2013-07-11T08:58:28.010 回答