66

我正在使用可扩展列表视图开发 android 应用程序。实际上我需要的是，我正在列出包含孩子的组。

如果我选择了一个不可展开的组，它应该展开，在我选择第二个组之后，第一个组应该被折叠。我做了谷歌，但我找不到我想要的。请帮帮我。

4

8 回答 8

208

将当前展开的组位置存储在变量中。在 onGroupExpanded 中执行以下操作。

private int lastExpandedPosition = -1;
private ExpandableListView lv; //your expandable listview
...

lv.setOnGroupExpandListener(new OnGroupExpandListener() {

    @Override
    public void onGroupExpand(int groupPosition) {
            if (lastExpandedPosition != -1
                    && groupPosition != lastExpandedPosition) {
                lv.collapseGroup(lastExpandedPosition);
            }
            lastExpandedPosition = groupPosition;
    }
});
于 2013-07-11T06:17:18.193 回答
29

使用此代码，这将起作用

expandableList.setOnGroupExpandListener(new OnGroupExpandListener() {
    int previousItem = -1;

    @Override
    public void onGroupExpand(int groupPosition) {
        if(groupPosition != previousItem )
            expandableList.collapseGroup(previousItem );
        previousItem = groupPosition;
    }
});
于 2013-07-11T06:11:34.877 回答
8 
@Override
    public void onGroupExpanded(int groupPosition){
        //collapse the old expanded group, if not the same
        //as new group to expand
        if(groupPosition != lastExpandedGroupPosition){
            listView.collapseGroup(lastExpandedGroupPosition);
        }

        super.onGroupExpanded(groupPosition);           
        lastExpandedGroupPosition = groupPosition;
    }
于 2013-07-11T06:16:58.673 回答
5

如果 ExpandableListView 有 2 个以上的组： 

expandableListView.setOnGroupExpandListener(new ExpandableListView.OnGroupExpandListener() {
    @Override
    public void onGroupExpand(int groupPosition) {
        for (int g = 0; g < expandableListAdapter.getGroupCount(); g++) {
            if (g != groupPosition) {
                expandableListView.collapseGroup(g);
            }
        }
    }
});

它将折叠除单击的组之外的所有组。

于 2017-04-07T07:43:33.363 回答
3

获取ExpendableListView然后覆盖以下方法 -setOnGroupExpandListener

expandableListView = (ExpandableListView) findViewById(R.id.exp_listview);

expandableListView.setOnGroupExpandListener(new ExpandableListView.OnGroupExpandListener() {
        int previousItem = -1;

        @Override
        public void onGroupExpand(int groupPosition) {
            if (groupPosition != previousItem)
                expandableListView.collapseGroup(previousItem);
            previousItem = groupPosition;
        }
    });
于 2015-12-30T19:22:04.203 回答
1

试着把它放在你的 ExpandableListAdapter 中，listView 是对 ExpandableListView 本身的引用。lastExpandedGroupPosition 是在 ExpandableListAdapter 中定义的整数成员变量。

 @Override
    public void onGroupExpanded(int groupPosition)

{

//collapse the old expanded group, if not the same

//as new group to expand

if(groupPosition != lastExpandedGroupPosition)

{

  listView.collapseGroup(lastExpandedGroupPosition);

  }

        super.onGroupExpanded(groupPosition);           
        lastExpandedGroupPosition = groupPosition;
    }
于 2015-07-30T11:41:01.287 回答
0 
   elstListView1.setOnGroupExpandListener(new ExpandableListView.OnGroupExpandListener() {
        @Override
        public void onGroupExpand(int groupPosition) {
            for(int i=0;i<listDataHeader.size();i++){
                if(i==groupPosition){
                    //do nothing}
                    else{
                        elstListView1.collapseGroup(i);
                    }
                }
            }
        });
于 2015-01-20T10:09:39.553 回答
-5

我也面临同样的问题。但我可以通过以下代码解决我的问题：

因为我的可扩展列表中有 4 个标题，基于我这样写

expListView.setOnGroupExpandListener(new OnGroupExpandListener() {

            @Override
            public void onGroupExpand(int groupPos) {
                // TODO Auto-generated method stub
                expListView.collapseGroup(groupPos+1);
                expListView.collapseGroup(groupPos-1);
                expListView.collapseGroup(groupPos-2);
                expListView.collapseGroup(groupPos+2);
                expListView.collapseGroup(groupPos+3);
                expListView.collapseGroup(groupPos-3);
            }
        });`
于 2014-10-07T11:39:25.247 回答