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我正在尝试在数据库中插入一个对象。它包含一个也应该插入的集合,但我得到以下异常:

SQLServerException: Cannot insert the value NULL into column 'ID_CUSTOMER', table 'dbo.CUSTOMER_ADDRESS'; column does not allow nulls. INSERT fails.

映射如下:

客户数据库.java

@OneToMany(fetch = FetchType.LAZY, mappedBy = "customer", orphanRemoval = true, cascade = CascadeType.ALL)
private List<CustomerAddressDB> addresses;

CustomerAddressDB.java

@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.REFRESH)
@JoinColumn(name = "ID_CUSTOMER", nullable = false, updatable=false, insertable=false)
private CustomerDB customer;

因此,当我为 CustomerDB 实体调用 persist 方法时,我可以看到 HQL 正在执行:

Hibernate: insert into M2M_CUSTOMER (NM_COMPANY_NAME, DT_CREATED, ID_PARENT, ID_LAYER, DS_OBS, DS_SHORT_NAME, ID_CUSTOMER_STATUS, NM_TRADING_NAME) values (?, ?, ?, ?, ?, ?, ?, ?)
Hibernate: insert into M2M_CUSTOMER_ADDRESS (DS_CITY, DS_COUNTRY, NR_NUMBER, NR_POSTAL_CODE, DS_STATE, DS_STREET, ID_ADDRESS_TYPE) values (?, ?, ?, ?, ?, ?, ?)

但在此之后,前面提到的异常被抛出。我不明白为什么它说 CUSTOMER_ID 为空,因为客户被插入到地址之前。有没有映射错误?

谢谢!

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1 回答 1

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您告诉 Hibernate 不应插入或更新 Address 实体中的客户,因此 Hibernate 不会插入它。代替

@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.REFRESH)
@JoinColumn(name = "ID_CUSTOMER", nullable = false, updatable=false, insertable=false)
private CustomerDB customer;

经过

@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.REFRESH)
@JoinColumn(name = "ID_CUSTOMER", nullable = false)
private CustomerDB customer;
于 2013-07-10T20:58:48.930 回答