php - 显示来自多维数组的值

Question

现在，这段代码显示了所有五种冰淇淋口味。我试图只展示库存中的口味。

   <pre><?php

   $flavors = array();
   $flavors[] = array("name" => "Cookie Dough",      "in_stock" => true);
   $flavors[] = array("name" => "Vanilla",           "in_stock" => false);
   $flavors[] = array("name" => "Avocado Chocolate", "in_stock" => false);
   $flavors[] = array("name" => "Bacon Me Crazy",    "in_stock" => true);
   $flavors[] = array("name" => "Strawberry",        "in_stock" => false);

   foreach($flavors as $flavor) {


    echo $flavor["name"] . "\n";


  }

  ?></pre>

Answer 1

这应该可以解决问题。

foreach($flavors as $flavor) {
   if($flavor['in_stock'] === true)
       echo $flavor["name"] . "\n";
}

Answer 2

$flavorsInStock = array_filter($flavors, function($flavor) {
    return $flavor['in_stock'];
});

将为您提供仅包含库存口味的新阵列。

Answer 3

您仍然可以使用 foreach 循环，但使用if语句检查库存

foreach($flavors as $flavor) {
  if ($flavor["in_stock"])
    echo $flavor["name"] . "\n";
}

Answer 4

代替

echo $flavor["name"] . "\n";

和

if ($flavor['in_stock']) {
  echo $flavor["name"] . "\n";
}

Answer 5

foreach($flavors as $flavor)
{
   if ($flavor['in_stock'])
   {
       echo $flavor["name"] . "\n";
   }
}