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每周，我的客户都会通过第三方营销小组开展广播节目和电子邮件活动，以推广他的产品。他想知道他每周赚/花多少钱，并为他分解数据。表数据如下所示：

tablename: orders
+----------+--------------+---------------------+------------+
| order_id | order_amount | referral            | order_date |
+----------+--------------+---------------------+------------+
| 1        | 16.00        | Radio: Jack Johnson | 2013-07-01 |
| 2        | 50.00        | Radio: Jack Johnson | 2013-07-02 |
| 3        | 16.00        | Radio: Jack Johnson | 2013-07-02 |
| 4        | 50.00        | Radio: Thabo Mbeki  | 2013-07-03 |
| 5        | 16.00        | Email: Renewal      | 2013-07-08 |
| 6        | 50.00        | Other               | 2013-07-08 |
| 7        | 16.00        | Email: Renewal      | 2013-07-08 |
| 8        | 50.00        | Radio: Thabo Mbeki  | 2013-07-09 |
+----------+--------------+--------------+-------------------+

tablename: media
+----------+-------+-------+--------------+-------+------------+
| media_id | spots | cost  | name         | type  | date       |
+----------+-------+-------+--------------+-------+------------+
| 1        | 10    | 10000 | Jack Johnson | radio | 2013-07-01 |
| 2        | 5     | 5000  | Thabo Mbeki  | radio | 2013-07-01 |
| 3        | 10    | 10000 | Jack Johnson | radio | 2013-07-08 |
| 4        | 5     | 5000  | Thabo Mbeki  | radio | 2013-07-08 |
| 5        | 1     | 250   | Renewal      | email | 2013-07-08 |
+----------+---------------+--------------+--------------------+

我需要生成一个这样的 HTML 表：

+------------+--------------+-------+------+----------+---------+--------------+----------------+
| week       | name         | type  |spots | cost     | revenue | total orders | avg. per order |
+------------+--------------+-------+------+----------+---------+--------------+----------------+
| 2013-07-01 | Jack Johnson | radio | 10   | 10000    | 82.00   | 3            | 27.33          |
| 2013-07-01 | Thabo Mbeki  | radio | 5    | 5000     | 50.00   | 1            | 50.00          |
+------------+--------------+-------+------+----------+---------+--------------+----------------+

我试图弄清楚如何加入表格并按订单中的推荐字段对它们进行分组对我来说变得很复杂。由于 orders.referral 与 media.name 不匹配，我猜有一个WHERE referral LIKE %name但我不知道该怎么做。

4

3 回答 3

0

如果您忽略“其他”，则更好的加入 WHERE 子句将是

WHERE orders.order_date = media.date
 AND  LOWER(orders.referral)   = LOWER(media.type + ": " + media.name)

这是 Sybase 语法，如果您需要为 MySQL 稍微调整一下，我深表歉意

要处理“其他”，只需对“媒体”表进行外部连接。

像（没有检查正确性）这样的东西会做一个按日期报告；如果您愿意，您将需要按周对它进行进一步按摩（这并不难，但我觉得超出了您问题的主要范围）

SELECT SUM(order.amount) AS revenue, COUNT(order.amount) as total_orders
      ,SUM(order.amount)/COUNT(order.amount) as average_order
      ,SUM(spots) spots, media.type, media.name, order_date
FROM   order
LEFT OUTER JOIN media 
ON        orders.order_date = media.date
     AND  LOWER(orders.referral)   = LOWER(media.type + ": " + media.name)
GROUP BY order.referral, order.date
-- May be add to group by:    , COALESCE(media.type,media.name,"Other")
于 2013-07-10T15:26:41.980 回答
0

我相信这应该有效：

SELECT m.name, [other needed columns]
FROM media m JOIN orders o ON o.referral LIKE '%' + m.name +'%'
WHERE m.date between [date] and [date]
GROUP BY m.name, [other groupings]

希望这可以帮助！

于 2013-07-10T15:32:49.643 回答
0

这里有很大的帮助。这是我最终使用的查询：

SELECT m.date, m.name, m.type, m.spots, m.cost, 
       SUM(o.order_amount) as revenue, 
       COUNT(o.order_amount) as orders,
       SUM(o.order_amount)/COUNT(o.order_amount) as average_order 
FROM   media m
JOIN   orders o
ON     LOWER(o.referral) = CONCAT(LOWER(m.type), ': ' ,LOWER(m.name))
WHERE  (DATE(o.order_date) BETWEEN '2013-06-24' AND '2013-06-30')
GROUP BY m.name, m.type
于 2013-07-11T15:04:49.593 回答