1

我有一个看起来或多或少像这样的查询：

INSERT INTO #results
SELECT Name, 
        (SELECT 
            SUM(CAST(Amount AS BIGINT)) 
         FROM Items 
         WHERE RemittingMember = a.Number 
            and RecordId = 50), 
        (SELECT SUM(CAST(Std_Amount AS BIGINT)) 
         FROM Items 
         WHERE RemittingMember = a.Number 
            AND RecordId = 10)
FROM Member a

whereAmount是一种货币（存储为 varchar，不带小数），是表和表RemittingMember之间的链接，并指示该行是什么类型的项目。在这种情况下，50 是借方，10 是贷方。ItemsMemberRecordId

我需要从第二列中减去第一列并将该值放在第三列中。我知道我可以这样做：

INSERT INTO #results
SELECT Name, 
            (SELECT 
                SUM(CAST(Amount AS BIGINT)) 
             FROM Items 
             WHERE RemittingMember = a.Number 
                and RecordId = 50), 
            (SELECT SUM(CAST(Std_Amount AS BIGINT)) 
             FROM Items 
             WHERE RemittingMember = a.Number 
                AND RecordId = 10),
             (SELECT 
                SUM(CAST(Amount AS BIGINT)) 
             FROM Items 
             WHERE RemittingMember = a.Number 
                and RecordId = 50) - (SELECT SUM(CAST(Std_Amount AS BIGINT)) 
             FROM Items 
             WHERE RemittingMember = a.Number 
                AND RecordId = 10)    
FROM Member a

但是，如果需要进行更改，这将很难阅读并且更改起来很麻烦。我也知道我可以使用局部变量来做到这一点，但这是一个a.Number将发生变化的报告，其中将涉及我想要避免的迭代。

我还需要检查第三列的符号以将值放入第四列。

有没有聪明的方法来实现这一点？

4

3 回答 3

1

您可以使用outer apply声明：

INSERT INTO #results
SELECT Name, 
        s1.Value, 
        s2.Value,
        s2.Value - s1.Value,
        case
            when s2.Value > s1.Value then 1
            when s2.Value < s1.Value then -1
            else 0
        end
FROM Member a
    outer apply (SELECT 
            SUM(CAST(Amount AS BIGINT)) Value
         FROM Items 
         WHERE RemittingMember = a.Number 
            and RecordId = 50) s1
    outer apply (SELECT 
            SUM(CAST(Std_Amount AS BIGINT)) Value
         FROM Items 
         WHERE RemittingMember = a.Number 
            and RecordId = 10) s2
于 2013-07-10T12:55:57.037 回答
1

您可以使用 CTE，如下所示：

;WITH intermediate_results (name, debit, credit)
AS (
SELECT
    Name
    AS name, 

    (SELECT 
        SUM(CAST(Amount AS BIGINT)) 
     FROM Items 
     WHERE RemittingMember = a.Number 
        and RecordId = 50)
    AS debit, 

    (SELECT SUM(CAST(Std_Amount AS BIGINT)) 
     FROM Items 
     WHERE RemittingMember = a.Number 
        AND RecordId = 10)
    AS credit

FROM Member a
)

INSERT INTO #results
SELECT name, debit, credit, debit - credit, SIGN(debit - credit)
  FROM intermediate_results
于 2013-07-10T13:02:32.650 回答
0

您应该能够进一步简化查询，以删除对 items 表的附加连接。像这样的东西应该工作。 需要用您的数据进行测试

SELECT
    name, 
    debit, 
    credit, 
    Amount = debit - credit, 
    [SIGN] = SIGN(debit - credit)
FROM Member a
inner join(
     SELECT 
        RemittingMember,
        debit=SUM(CASE WHEN RecordId = 50 THEN CAST(Amount AS BIGINT) ELSE 0 END),
        credit=SUM(CASE WHEN RecordId = 10 THEN CAST(Std_Amount AS BIGINT) ELSE 0 END)
     FROM Items 
     WHERE RecordId IN(10,50)
     GROUP BY
        RemittingMember
) as Amts
    on Amts.RemittingMember = a.Number
于 2013-07-10T17:41:55.273 回答