scala - 在视图中播放框架 Scala 元组

Question

我正在尝试比较两个 Seq 字符串，这是我使用 Apache LDAP API 和 Play 获得的！Scala 框架。几天后，我没有想法了。这是开头：

@(compares:Seq[Compare] , compares1:Seq[Compare], compareForm: Form[(String, String)])(隐式请求:Request[Any])

@import 助手._

@main("管理工具", request.uri){

我有两个交互 - 如何比较它们？

@for(compare <- compares) {
    <td>@for(group <- compare.memberOf) {
        <li style="list-style-type: none;">@group.replaceAll(",(.*)","").replaceAll("(.*)=","")</li>
    }</td>
}
@for(compare1 <- compares1) {
    <td>@for(group1 <- compare1.memberOf) {
        <li style="list-style-type: none;">@group1.replaceAll(",(.*)","").replaceAll("(.*)=","")</li>
    }</td>
}   

Answer 1

我知道这可能是一个迟到的答案，但我当时设法解决了这个问题。代码可能有点脏，但我希望它对某人有用。

模型部分：

def intersection(c1:Seq[String], c2:Seq[String]): Seq[String] = {
    (Set(c1: _*) & Set(c2: _*)).toSeq
}

控制器部分：

compareForm.bindFromRequest.fold(
hasErrors = {errors => BadRequest(views.html.compares.index(compareForm, username, User.find(username)))},
success = { ldapName => 
  val leftUser = Compare.findAll(ldapName._1)
  val rightUser = Compare.findAll(ldapName._2)
  val intersection = Compare.intersection(leftUser.memberOf,rightUser.memberOf) 
  val rightLacking: Seq[String] = (leftUser.memberOf.toSet -- intersection.toSet).toList.map(_.toString).sorted      
  val leftLacking: Seq[String] = (rightUser.memberOf.toSet -- intersection.toSet).toList.map(_.toString).sorted
  val bothOk: Seq[String] = (intersection.toSet).toList.sorted
  Ok(views.html.compares.list(leftUser, rightUser, rightLacking, leftLacking, bothOk, compareForm, username, User.find(username)))
}  )

问候！