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在使用 MVVM 开发小型 Windows Store 应用程序时,我遇到了一个棘手的问题。我想使用 ListBox 显示来自 Big Brother 第 14 季的房客列表。按照设计,每个 ListBoxItem 中都应该有一个按钮。单击按钮时,应触发一个命令,该命令将从 ListBox 中删除 ListBoxItem。

以下是我目前的解决方案。它可以工作,但不是很令人满意,因为每当从 ListBox 中删除一个项目时,模型都需要过滤整个集合并刷新整个 ListBox,这会导致一些性能问题,尤其是当原始集合非常庞大时。

[主页.xaml]

<Page
    x:Class="App1.MainPage"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:local="using:App1"
    xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
    xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
    mc:Ignorable="d">

    <Page.Resources>
        <CollectionViewSource x:Name="groupInfo" IsSourceGrouped="true" ItemsPath="Items" />
        <local:BigBrotherModel x:Name="BBModel" />
        <DataTemplate x:Key="lvwItemTemp">
            <StackPanel>
                <Grid  Height="30">
                    <Grid.ColumnDefinitions>
                        <ColumnDefinition Width="40" />
                        <ColumnDefinition Width="100" />
                        <ColumnDefinition Width="100" />
                    </Grid.ColumnDefinitions>

                    <Button  Grid.Column="0" Padding="0" Foreground="Red" FontFamily="Segoe UI Symbol"
                                Command="{Binding DataContext.RemoveHouseGuestCommand, ElementName=lbxHouseGuests}" 
                                CommandParameter="{Binding}">&#xE221;</Button>
                    <TextBlock Grid.Column="1" Text="{Binding FirstName}" HorizontalAlignment="Stretch" />
                    <TextBlock Grid.Column="2" Text="{Binding LastName}" HorizontalAlignment="Stretch"  />
                </Grid>
            </StackPanel>
        </DataTemplate>
    </Page.Resources>


    <Grid Background="{StaticResource ApplicationPageBackgroundThemeBrush}">
        <ListBox x:Name="lbxHouseGuests" DataContext="{StaticResource BBModel}" ItemsSource="{Binding Source={StaticResource groupInfo}}" ItemTemplate="{StaticResource lvwItemTemp}" HorizontalAlignment="Stretch" VerticalAlignment="Stretch">
            <ListBox.GroupStyle>
                <GroupStyle>
                    <GroupStyle.HeaderTemplate>
                        <DataTemplate>
                            <Border BorderBrush="Red" BorderThickness="0" Background="DarkGray" HorizontalAlignment="Stretch">
                                <TextBlock Width="500" Text="{Binding Role}"/>
                            </Border>
                        </DataTemplate>
                    </GroupStyle.HeaderTemplate>
                </GroupStyle>
            </ListBox.GroupStyle>
        </ListBox>
    </Grid>
</Page>

[主页.cs]

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Windows.Input;
using Windows.Foundation;
using Windows.Foundation.Collections;
using System.Collections.ObjectModel;
using Windows.UI.Xaml;
using Windows.UI.Xaml.Controls;
using Windows.UI.Xaml.Controls.Primitives;
using Windows.UI.Xaml.Data;
using Windows.UI.Xaml.Input;
using Windows.UI.Xaml.Media;
using Windows.UI.Xaml.Navigation;
using Windows.UI.Popups;
using System.Diagnostics;


namespace App1
{


    public class HouseGuest
    {
        public string FirstName { get; set; }
        public string LastName { get; set; }
        public string Role { get; set; }
        public bool Deleted { get; set; }
    }

    public class BigBrotherModel
    {
        public ObservableCollection<HouseGuest> houseGuests { get; set; }
        public ListBox lbx { get; set; }
        public CollectionViewSource cvs { get; set; }

        public BigBrotherModel()
        {
            houseGuests = new ObservableCollection<HouseGuest>();
            houseGuests.Add(new HouseGuest() { FirstName = "Ian", LastName = "Terry", Role="Player" });
            houseGuests.Add(new HouseGuest() { FirstName = "Shane", LastName = "Meaney", Role = "Player" });
            houseGuests.Add(new HouseGuest() { FirstName = "Wil", LastName = "Heuser", Role = "Player" });
            houseGuests.Add(new HouseGuest() { FirstName = "Danielle", LastName = "Murphree", Role = "Player" });
            houseGuests.Add(new HouseGuest() { FirstName = "Jenn", LastName = "Arroyo", Role = "Player" });
            houseGuests.Add(new HouseGuest() { FirstName = "Jodi", LastName = "Rollins", Role = "Player" });
            houseGuests.Add(new HouseGuest() { FirstName = "Ashley", LastName = "Iocco", Role = "Player" });

            houseGuests.Add(new HouseGuest() { FirstName = "Britney", LastName = "Haynes", Role = "Coach" });
            houseGuests.Add(new HouseGuest() { FirstName = "Dan", LastName = "Gheesling", Role = "Coach"});
            houseGuests.Add(new HouseGuest() { FirstName = "Janelle", LastName = "Pierzina", Role = "Coach" });
            houseGuests.Add(new HouseGuest() { FirstName = "Mike", LastName = "Boogie", Role = "Coach"});


            RemoveHouseGuestCommand = new DelegateCommand(RemoveHouseGuest);
        }
        public ICommand RemoveHouseGuestCommand { get; set; }

        void RemoveHouseGuest(object param)
        {
            Debug.Assert(param is HouseGuest);
            (param as HouseGuest).Deleted = true;
            RefreshListBox();
        }

        object GetGroupedView()
        {
            var view = from hg in houseGuests
                       where hg.Deleted == false
                       group hg by hg.Role into g
                       orderby g.Key
                       select new { Role = g.Key, Items = g };
            return view;
        }

        public void RefreshListBox()
        {
            cvs.Source = GetGroupedView();
        }
    }

    public sealed partial class MainPage : Page
    {

        public MainPage()
        {
            this.InitializeComponent();
            BBModel.cvs = groupInfo;
            BBModel.lbx = lbxHouseGuests;

            BBModel.RefreshListBox();
        }
    }
}

我的问题是:有没有办法从分组的 ListBox 中删除 ListBoxItem 而无需使用 MVVM 刷新整个 ListBox?我真的被困在这里了。任何建议将不胜感激。提前谢谢了。

[编辑] 感谢 Nate 的建议,我在 MainPage.cs 中重写了我的代码,效果很好。这是源代码。

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Windows.Input;
using Windows.Foundation;
using Windows.Foundation.Collections;
using System.Collections.ObjectModel;
using Windows.UI.Xaml;
using Windows.UI.Xaml.Controls;
using Windows.UI.Xaml.Controls.Primitives;
using Windows.UI.Xaml.Data;
using Windows.UI.Xaml.Input;
using Windows.UI.Xaml.Media;
using Windows.UI.Xaml.Navigation;
using Windows.UI.Popups;
using System.Diagnostics;
using System.Collections.Specialized;


namespace App1
{


    public class HouseGuest
    {
        public string FirstName { get; set; }
        public string LastName { get; set; }
        public string Role { get; set; }
        public bool Deleted { get; set; }
    }

    public class HouseGuestGroup : IGrouping<string, HouseGuest>
    {
        public ObservableCollection<HouseGuest> Items { get; set; }
        public string Role { get; set; }
        public HouseGuestGroup()
        {
            Items = new ObservableCollection<HouseGuest>();
        }

        public string Key
        {
            get { return Role; }
        }

        public IEnumerator<HouseGuest> GetEnumerator()
        {
            return Items.GetEnumerator();
        }

        System.Collections.IEnumerator System.Collections.IEnumerable.GetEnumerator()
        {
            return Items.GetEnumerator();
        }


    }

    public class BigBrotherModel : ObservableCollection<HouseGuestGroup>
    {
        public BigBrotherModel()
        {
            RemoveHouseGuestCommand = new DelegateCommand(RemoveHouseGuest);
        }

        public ICommand RemoveHouseGuestCommand { get; set; }

        void RemoveHouseGuest(object param)
        {
            Debug.Assert(param is HouseGuest);
            HouseGuest guest = param as HouseGuest;

            foreach (var g in Items)
            {
                if (g.Role == guest.Role)
                {
                    g.Items.Remove(guest);
                    break;
                }
            }
        }

    }

    public sealed partial class MainPage : Page
    {

        public MainPage()
        {
            this.InitializeComponent();

            HouseGuestGroup guestGroup;

            guestGroup = new HouseGuestGroup();
            guestGroup.Role = "Coach";
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Britney", LastName = "Haynes", Role = "Coach" });
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Dan", LastName = "Gheesling", Role = "Coach" });
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Janelle", LastName = "Pierzina", Role = "Coach" });
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Mike", LastName = "Boogie", Role = "Coach" });
            BBModel.Add(guestGroup);



            guestGroup = new HouseGuestGroup();
            guestGroup.Role = "Player";
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Ian", LastName = "Terry", Role = "Player" });
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Shane", LastName = "Meaney", Role = "Player" });
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Wil", LastName = "Heuser", Role = "Player" });
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Danielle", LastName = "Murphree", Role = "Player" });
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Jenn", LastName = "Arroyo", Role = "Player" });
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Jodi", LastName = "Rollins", Role = "Player" });
            guestGroup.Items.Add(new HouseGuest() { FirstName = "Ashley", LastName = "Iocco", Role = "Player" });
            BBModel.Add(guestGroup);

            groupInfo.Source = BBModel;
        }
    }
}

顺便说一句,我认为最好让这个问题保持开放,希望最终能出现一些更好的解决方案。

4

1 回答 1

0

正在发生的事情是 LINQ 语句每次都创建一个新列表,因此当您影响可观察集合时,它不会被反映,因为它们是两个不同的列表。您需要做的是创建一个自定义 Group 对象,其中包含一个 ObservableCollection 来存储客人。然后,您必须创建这些组的 ObservableCollection。然后,您可以对静态集合(或任何子集合)进行任何更改,它将反映在您的视图中。

然后,您可以对给定的可观察集合做一些简单而直接的事情,例如

void RemoveHouseGuest(object param)
{
    Debug.Assert(param is HouseGuest);
    if(houseGuests.Contains(param as HouseGuest))
        houseGuests.Remove(param);
    //(param as HouseGuest).Deleted = true;
    //RefreshListBox();
}

希望这对编码有所帮助和快乐!

于 2013-07-11T16:22:12.673 回答