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我在工作中使用 Java 应用程序。我需要将点击发送到按钮并填写文本框。我希望这些动作在后台发生。窗口的ahk_class是 SunAwtFrame，并且没有任何控件暴露给 WindowSpy。

我使用 JavaFerret 确定我要按下的第一个按钮有AccessibleAction

Version Information:
    Java virtual machine version: 1.7.0_25
    Access Bridge Java class version: 1.7.0_25
    Access Bridge Java DLL version: AccessBridge 2.0.2
    Access Bridge Windows DLL version: AccessBridge 2.0.2

AccessibleContext information:
    Name:  New Call
    Description:  Place a new call
    Role:  push button
    Role in en_US locale:  push button
    States:  enabled,focusable,visible,showing,opaque
    States in en_US locale:  enabled,focusable,visible,showing,opaque
    Index in parent:  1
    Children count:  0
    Bounding rectangle:  [288, 317, 385, 376]
    Top-level window name:  Phone Assistant: 
    Top-level window role:  frame
    Parent name:  
    Parent role:  panel
    Visible descendents count:  0

AccessibleIcons info:
    Number of icons:  1
    Icon 0 description: jar:http://proxy.m5net.com/vox/pa/receptioncenter.jar!/resources/phone.png
    Icon 0 height: 26
    Icon 0 width: 27

AccessibleActions info:
    Number of actions:  1
    Action 0 name: click

Accessible Value information:
    Current Value:  0
    Maximum Value:  1
    Minimum Value:  0

可访问性文档告诉我，我应该告诉对象执行该操作，但我不知道该怎么做。

最好使用 AutoHotkey，如何做到这一点？

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