我有一个未确定级别的 json 树,如下所示:
var nodeset = {
"name" : "FORM",
"attributes" : {
"IDFORM" : "59",
"NOMDOC" : "1",
"VERSFORM" : "1.01",
"DATEREPORT" : "10.10.1988"
},
"nodes" : [{
"name" : "PART1",
"persist" : true,
"nodes" : [{
"name" : "FTYPE",
"persist" : true,
"value" : "1",
"weight" : 1
}, {
"name" : "STARTDATE",
"persist" : true,
"value" : "01.10.2011",
"weight" : 1
}, {
"name" : "ENDDATE",
"persist" : true,
"value" : "31.12.2011",
"weight" : 1
}
],
"value" : "31.12.2011",
"weight" : 3
}, {
"name" : "PART2",
"persist" : true,
"nodes" : [{
"name" : "F203",
"persist" : true,
"value" : 12,
"weight" : 1
}, {
"name" : "F204",
"persist" : true,
"value" : 12,
"weight" : 1
}, {
"name" : "STI059DETAIL",
"persist" : false,
"nodes" : [{
"name" : "F1",
"persist" : false,
"value" : "asd",
"weight" : 1
}, {
"name" : "F2",
"persist" : false,
"value" : "asd",
"weight" : 1
}, {
"name" : "F3",
"persist" : false,
"value" : 0,
"weight" : 0
}, {
"name" : "F4",
"persist" : false,
"value" : 0,
"weight" : 0
}
],
"value" : 0,
"weight" : 2
}, {
"name" : "STI059DETAIL",
"persist" : false,
"nodes" : [{
"name" : "F1",
"persist" : false,
"value" : null,
"weight" : 0
}, {
"name" : "F2",
"persist" : false,
"value" : null,
"weight" : 0
}, {
"name" : "F3",
"persist" : false,
"value" : 0,
"weight" : 0
}, {
"name" : "F4",
"persist" : false,
"value" : 0,
"weight" : 0
}
],
"value" : 0,
"weight" : 0
}, {
"name" : "STI059DETAIL",
"persist" : false,
"nodes" : [{
"name" : "F1",
"persist" : false,
"value" : null,
"weight" : 0
}, {
"name" : "F2",
"persist" : false,
"value" : null,
"weight" : 0
}, {
"name" : "F3",
"persist" : false,
"value" : 0,
"weight" : 0
}, {
"name" : "F4",
"persist" : false,
"value" : 0,
"weight" : 0
}
],
"value" : 0,
"weight" : 0
}
],
"value" : 0,
"weight" : 4
}
],
"weight" : 7
};
weight
我的任务是从其中删除所有节点0
以及nodes
属性存在的位置。
因为它是一棵树,所以我尝试使用这样的递归函数:
function clean(index, owner){
var node = owner[index],
weight = node.weight;
delete node.weight;
if(typeof node.persist != 'undefined'){
delete node.persist;
}
if(!node.nodes)return;
if(!weight){
owner.splice(index, 1);
}
for(var i = 0; i < node.nodes.length; i++){
clean(i, node.nodes);
}
}
for(var i = 0; i < nodeset.nodes.length; i++){
clean(i, nodeset.nodes);
}
但splice()
不知何故,并没有从那里删除任何东西。我已将其替换为delete owner[index]
,这会导致null
这些节点的位置出现值(我不想在那里看到:(
)。
我的问题:为什么该splice()
功能没有按我的预期工作(不删除节点)?另外,我采取了正确的方法吗?如果没有,那么任何其他建议将不胜感激。
问候。
在这里测试小提琴,如果它可能会有所帮助。