我会告诉你一个方法。为此,我将您的代码重写如下:
local mRandom = math.random
local objects = {"rocket02" ,"rocket01","coin01"}
local objectTag = 0
local object = {}
local function spawnObject()
objectTag = objectTag + 1
local objIdx = mRandom(#objects)
local objName = objects[objIdx]
object[objectTag] = display.newImage(objName..".png") -- see the difference here
object[objectTag].x = 30+mRandom(320)
object[objectTag].y = 200
object[objectTag].name = objectTag
print(objectTag)
end
timer.performWithDelay(1,spawnObject,3)
在这里,我使用了 atimer
来显示对象。您也可以将 for 循环用于相同目的。在这里,您可以将任何带有标签的对象称为object[objectTag]
.
供您参考:
display.newImage(objName..".png")
--[[ will display object named rocket02.png or rocket01.png or coin01.png
placed in the same folder where your main.lua resides --]]
和
display.newImage("image/object_"..objName..".png")
--[[ will display object named object_rocket02.png or object_rocket01.png
or object_coin01.png placed in a folder named 'image'. And the folder
'image' should reside in the same folder where your main.lua is. --]]
对于从上到下移动对象,您可以使用:
任何一个
function moveDown()
object[objectTag].y = object[objectTag].y + 10
--replace 'objectTag' in above line with desired number (ir., 1 or 2 or 3)
end
timer.performWithDelay(100,moveDown,-1)
或者
transition.to(object[objectTag],{time=1000,y=480})
--[[ replace 'objectTag' in above line with desired number (ir., 1 or 2 or 3)
eg: transition.to(object[1],{time=1000,y=480}) --]]
继续编码........ :)