在我的程序中,我需要用户能够通过命令行命名“豌豆植物”。我正在使用 fgets,并且由于我不希望名称中允许有空格,因此我设置了一个 while 循环,该循环通过 rangeOfString 生成在字符串中具有空格的任何名称条目。这几乎一直有效——当用户输入一个没有空格的字符串时,它会让它通过,而当他们输入一个空格或多个空格时,它通常会阻止它们。但是,我发现了两个给出意外结果的字符串:“nyan nyan cat cat”(实际上并未输入引号)在您只输入一次时连续给出两个正确的错误报告。“is a pea plant” 给出一次正确的错误报告,然后让最后两个字母“nt”通过。
为什么会这样?
我怎样才能解决这个问题?
#import "Pea.h"
int main (int agrc, char * argv[])
{
@autoreleasepool {
int numb1 = 1;
Pea *pea1 = [[Pea alloc] init]; char word1[13];
while( numb1 == 1) {
NSLog(@"What would you like to name this pea?");
fgets(word1, 13, stdin);
size_t length1 = strlen(word1);
if(word1 [length1-1] == '\n') // In case that the input string has 12 characters plus '\n'
word1 [length1-1] = '\0'; // Plus '\0', the '\n' isn't added and the if condition is false.
NSString* userInput1 = [NSString stringWithUTF8String: word1];
[pea1 setName: userInput1];
//Makes sure string contains no spaces (spaces cause an error, and if I were to allow them in the name it would be easier in the future to forge messages out of a plant name.)
if ([pea1.name rangeOfString:@" " ].location == NSNotFound) {
NSLog(@"The pea plant has been successfully named %@", [pea1 name]);
numb1 = 0;
}
else {
NSLog(@"The pea plant has not been named because you have included a space in it!");
numb1 = 1;
}
}