1

我在服务器的同一目录中有两个 php 文件（http://www.xxxx.com/php/），

1) write_json.php


    $address['http_client'] = $_SERVER['HTTP_CLIENT_IP'];
    $address['http_x_forwarded_for'] = $_SERVER['HTTP_X_FORWARDED_FOR'];
    $address['http_x_forwarded'] = $_SERVER['HTTP_X_FORWARDED'];
    $address['http_forwarded_for'] = $_SERVER['HTTP_FORWARDED_FOR'];
    $address['http_forwarded'] = $_SERVER['HTTP_FORWARDED'];
    $address['remote_addr'] = $_SERVER['REMOTE_ADDR'];

    header('Content-Type: application/json');
    回声 json_encode($address);

2）get_ip.php

    $json_url = $_SERVER['SERVER_NAME'] 。'/php/write_json.php';

    $json_string = '';
    $ch = curl_init($json_url);


    $options = 数组（CURLOPT_RETURNTRANSFER => 真，
                         CURLOPT_HTTPHEADER => array('Content-type: application/json'),
                         CURLOPT_POSTFIELDS => $json_string);

    curl_setopt_array($ch, $options);

    $json_string = curl_exec($ch);
    回声 $json_string;

get_ip.php    调用   write_json.php

如果我们假设客户端 IP 是：76.2.35.46 而服务器一个是： 80.59.3.23 ，当我 在客户端浏览器上
调用http://www.xxxx.com/php/get_ip.php时

它向我显示服务器 IP 而不是客户端 IP，如下所示：

{
    http_client：空，
    http_x_forwarded_for：空，
    http_x_forwarded：空，
    http_forwarded_for：空，
    http_forwarded：空，
    远程地址：“80.59.3.23”
}

如何获取客户端 IP 而不是服务器 IP？

4

3 回答 3

2

您正在通过 curl 从服务器调用 write_json ......也就是说，服务器实际上正在请求 write_json 文件，因此 write_json 看到请求来自服务器。为什么不直接使用 include 而不是 curl 调用？

于 2013-07-09T22:52:00.660 回答
0

尝试获取客户端 IP 使用以下将返回客户端 IP 的函数

// Function to get the client IP address
function get_client_ip() {
    $ipaddress = '';
    if (getenv('HTTP_CLIENT_IP'))
        $ipaddress = getenv('HTTP_CLIENT_IP');
   else if(getenv('HTTP_X_FORWARDED_FOR'))
        $ipaddress = getenv('HTTP_X_FORWARDED_FOR');
   else if(getenv('HTTP_X_FORWARDED'))
        $ipaddress = getenv('HTTP_X_FORWARDED');
   else if(getenv('HTTP_FORWARDED_FOR'))
       $ipaddress = getenv('HTTP_FORWARDED_FOR');
   else if(getenv('HTTP_FORWARDED'))
       $ipaddress = getenv('HTTP_FORWARDED');
   else if(getenv('REMOTE_ADDR'))
       $ipaddress = getenv('REMOTE_ADDR');
   else
       $ipaddress = 'UNKNOWN';
   return $ipaddress;
}

在变量中获取 IP 后，然后发送

于 2018-03-12T15:59:39.320 回答
0

这种方式是不可能的。您需要先获取客户端 ip，然后通过 curl 将其作为发布的数据发送到服务器。

于 2016-09-23T06:06:21.020 回答