我必须在 Linux 中将任务设置为进程,但我不希望在创建所有进程之前执行该进程。所以我想在创建后不久将进程移动到等待队列,并等到所有进程都创建完毕。
#include <unistd.h> /* Symbolic Constants */
#include <sys/types.h> /* Primitive System Data Types */
#include <errno.h> /* Errors */
#include <stdio.h> /* Input/Output */
#include <stdlib.h> /* General Utilities */
#include <pthread.h> /* POSIX Threads */
#include <string.h> /* String handling */
#include <sched.h>
#include <linux/kernel.h>
#include <time.h>
#include <sys/resource.h>
#include <stddef.h>
#include <linux/sched.h>
#include <linux/wait.h> /* for wait_event_interruptible() & wake_up_interruptible() */
int done = 0;
static DECLARE_WAIT_QUEUE_HEAD(queue);
int main()
{
int pid1, pid2;
if ((pid1 = fork()) < 0) //create a child process
exit(1);
if ((pid2 = fork()) < 0) //create a child process
exit(1);
if (pid1 == 0) //child process
{
wait_event_interruptible(queue, done == 2);
printf("child 1\n");
}
else //parent process
{
done = done+1;
wake_up_interruptible(&queue);
}
if (pid2 == 0) //child process
{
wait_event_interruptible(queue, done == 2);
printf("child 2\n");
}
else //parent process
{
done = done+1;
wake_up_interruptible(&queue);
}
return 0;
}
但是当我尝试这个示例代码时,它显示了这些错误。
$ gcc -Wall try.c
try.c:18:8: warning: type defaults to ‘int’ in declaration of ‘DECLARE_WAIT_QUEUE_HEAD’ [-Wimplicit-int]
try.c:18:1: warning: parameter names (without types) in function declaration [enabled by default]
try.c: In function ‘main’:
try.c:33:6: warning: implicit declaration of function ‘wait_event_interruptible’ [-Wimplicit-function-declaration]
try.c:33:31: error: ‘queue’ undeclared (first use in this function)
try.c:33:31: note: each undeclared identifier is reported only once for each function it appears in
try.c:39:2: warning: implicit declaration of function ‘wake_up_interruptible’ [-Wimplicit-function-declaration]
try.c: At top level:
try.c:18:8: warning: ‘DECLARE_WAIT_QUEUE_HEAD’ declared ‘static’ but never defined [-Wunused-function]
当我检查 $ man wait_event_interruptible 时,它显示“没有手动输入 wait_event_interruptible”。因此库中缺少 API。如何将其添加到库中?提前致谢。