1

在为网站开发应用程序时。我一直在尝试解决这个问题一个星期左右，在谷歌上搜索了很多！而且我似乎找不到解决方案。我有一个 JSON 字符串，它是：

{
   "error":"",
   "S8tf":{
      "infoToken":"wCfhXe",
      "deleteToken":"gzHTfGcF",
      "size":122484,
      "sha1":"8c4e2bbc0794d2bd4f901a36627e555c068a94e6",
      "filename":"Screen_Shot_2013-07-02_at_3.52.23_PM.png"
   },
   "S29N":{
      "infoToken":"joRm6p",
      "deleteToken":"IL5STLhq",
      "size":129332,
      "sha1":"b4a03897121d0320b82059c36f7a10a8ef4c113d",
      "filename":"Stockholmsyndromet.docx"
   }
}

我希望它确实像 JSON 数组，所以我不必搜索“S8tf”和“S29N”，因为这是由服务器随机生成的。如果你明白我的意思？（不善于解释）。

我似乎无法从“错误”中获取所有信息并显示出来。我已经尝试过任何东西，但我似乎仍然无法弄清楚。

活动：（教程，应该工作）

package com.androidhive.jsonparsing;

import java.util.ArrayList;
import java.util.HashMap;

import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import android.app.ListActivity;
import android.content.Intent;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ListAdapter;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.TextView;

public class AndroidJSONParsingActivity extends ListActivity {

    // url to make request
    private static String url = "http://api.bayfiles.net/v1/account/files?session=7je10rvdhr1mcvjam75hetaul0";

    // JSON Node names
    private static final String TAG_CONTACTS = "error";
    private static final String TAG_ID = "id";
    private static final String TAG_NAME = "name";
    private static final String TAG_EMAIL = "email";
    private static final String TAG_ADDRESS = "address";
    private static final String TAG_GENDER = "gender";
    private static final String TAG_PHONE = "phone";
    private static final String TAG_PHONE_MOBILE = "mobile";
    private static final String TAG_PHONE_HOME = "home";
    private static final String TAG_PHONE_OFFICE = "office";

    // contacts JSONArray
    JSONArray contacts = null;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        // Hashmap for ListView
        ArrayList<HashMap<String, String>> contactList = new ArrayList<HashMap<String, String>>();

        // Creating JSON Parser instance
        JSONParser jParser = new JSONParser();

        // getting JSON string from URL
        JSONObject json = jParser.getJSONFromUrl(url);

        try {
            // Getting Array of Contacts
            contacts = json.getJSONArray(TAG_CONTACTS);

            // looping through All Contacts
            for(int i = 0; i < contacts.length(); i++){
                JSONObject c = contacts.getJSONObject(i);

                // Storing each json item in variable
                String id = c.getString(TAG_ID);
                String name = c.getString(TAG_NAME);
                String email = c.getString(TAG_EMAIL);
                String address = c.getString(TAG_ADDRESS);
                String gender = c.getString(TAG_GENDER);

                // Phone number is agin JSON Object
                JSONObject phone = c.getJSONObject(TAG_PHONE);
                String mobile = phone.getString(TAG_PHONE_MOBILE);
                String home = phone.getString(TAG_PHONE_HOME);
                String office = phone.getString(TAG_PHONE_OFFICE);

                // creating new HashMap
                HashMap<String, String> map = new HashMap<String, String>();

                // adding each child node to HashMap key => value
                map.put(TAG_ID, id);
                map.put(TAG_NAME, name);
                map.put(TAG_EMAIL, email);
                map.put(TAG_PHONE_MOBILE, mobile);

                // adding HashList to ArrayList
                contactList.add(map);
            }
        } catch (JSONException e) {
            e.printStackTrace();
        }


        /**
         * Updating parsed JSON data into ListView
         * */
        ListAdapter adapter = new SimpleAdapter(this, contactList,
                R.layout.list_item,
                new String[] { TAG_NAME, TAG_EMAIL, TAG_PHONE_MOBILE }, new int[] {
                        R.id.name, R.id.email, R.id.mobile });

        setListAdapter(adapter);

        // selecting single ListView item
        ListView lv = getListView();

        // Launching new screen on Selecting Single ListItem
        lv.setOnItemClickListener(new OnItemClickListener() {

            @Override
            public void onItemClick(AdapterView<?> parent, View view,
                    int position, long id) {
                // getting values from selected ListItem
                String name = ((TextView) view.findViewById(R.id.name)).getText().toString();
                String cost = ((TextView) view.findViewById(R.id.email)).getText().toString();
                String description = ((TextView) view.findViewById(R.id.mobile)).getText().toString();

                // Starting new intent
                Intent in = new Intent(getApplicationContext(), SingleMenuItemActivity.class);
                in.putExtra(TAG_NAME, name);
                in.putExtra(TAG_EMAIL, cost);
                in.putExtra(TAG_PHONE_MOBILE, description);
                startActivity(in);

            }
        });



    }

}

编辑：我知道看到 OP 让它工作是多么令人恼火，但没有任何类型的代码。所以我会发布对我有用的代码:)

public class FilesActivity extends SherlockListActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.dblist);

        getSupportActionBar().setDisplayHomeAsUpEnabled(true);
        getSupportActionBar().setTitle("Files");

        String response = null;
        DefaultHttpClient httpClient = new DefaultHttpClient();
        ResponseHandler <String> resonseHandler = new BasicResponseHandler();
        HttpPost postMethod = new HttpPost("URL");

        try
        {
        JSONObject json = new JSONObject();
               json.put("filename", "error");
               //json.put("Fiedl2", "");

               postMethod.setEntity(new ByteArrayEntity(json.toString().getBytes("UTF8")));
               postMethod.setHeader( "Content-Type", "application/json" );
               response = httpClient.execute(postMethod,resonseHandler);
               TextView txt = (TextView)findViewById(R.id.nodata);

               //JSONObject mJsonObject = new JSONObject(response);
               //JSONObject userJObject = mJsonObject.getJSONObject("error");
               JSONObject request = new JSONObject(response);
               for (Iterator keyIterator = request.keys(); keyIterator.hasNext(); ) {
                   // will be set to "S29N", "S8tf", "error" etc
                   String key = (String) keyIterator.next();
                   // will get value if it's an JSONObject or null if it's not
                   JSONObject object = request.optJSONObject(key);

                   if (object != null) {
                       //doSomething(object); // ← process the object
                       txt.setText(object.toString());
                       Log.d("log_tag", object.toString());
                   }
               }

        }
        catch(Exception e)
        {      
            e.printStackTrace();
            Log.d("log_tag", "Error: " + e.toString());

        }
    }

非常感谢你们！

4

4 回答 4

2

让我们重新格式化它作为开始。

{
  "S29N": {
    "deleteToken": "IL5STLhq",
    "filename": "Stockholmsyndromet.docx",
    "infoToken": "joRm6p",
    "sha1": "b4a03897121d0320b82059c36f7a10a8ef4c113d",
    "size": 129332
  },
  "S8tf": {
    "deleteToken": "gzHTfGcF",
    "filename": "Screen_Shot_2013-07-02_at_3.52.23_PM.png",
    "infoToken": "wCfhXe",
    "sha1": "8c4e2bbc0794d2bd4f901a36627e555c068a94e6",
    "size": 122484
  },
  "error": ""
}

因此，您似乎想要实现的是迭代 S29N、S8tf 等对象以及任何其他对象，前提是它们确实是对象。这是可行的（代码未经测试）：

// let's say sourceString is the variable holding the JSON text
JSONObject request = new JSONObject(sourceString);
for (Iterator keyIterator = request.keys(); keyIterator.hasNext(); ) {
    // will be set to "S29N", "S8tf", "error" etc
    String key = (String) keyIterator.next();
    // will get value if it's an JSONObject or null if it's not
    JSONObject object = request.optJSONObject(key);

    if (object != null) {
        doSomething(object); // ← process the object
    }
}

对不起，如果它没有帮助 - 在你发布更新的问题之前我已经回答了，现在我真的被 java 源震惊了，因为我无法弄清楚你收到的数据与你的数据的关系是显示（前者似乎是一些文件操作请求，后者 - 一些个人联系数据）。

于 2013-07-09T17:19:08.710 回答
2

你没有得到任何“错误”价值的原因是因为没有:)

看"error":""

此外，看起来您正在尝试获取 JSON 数组，但 JSON 对象中没有单个数组可以获取。要使您的代码正常工作，您需要 JSON 对象如下所示：

{
   "error":[],
   "S8tf":[{
      "infoToken":"wCfhXe",
      "deleteToken":"gzHTfGcF",
      "size":122484,
      "sha1":"8c4e2bbc0794d2bd4f901a36627e555c068a94e6",
      "filename":"Screen_Shot_2013-07-02_at_3.52.23_PM.png"
   }],
   "S29N":[{
      "infoToken":"joRm6p",
      "deleteToken":"IL5STLhq",
      "size":129332,
      "sha1":"b4a03897121d0320b82059c36f7a10a8ef4c113d",
      "filename":"Stockholmsyndromet.docx"
   }]
}

由于某些基本节点名称是未知的（如您所说，由服务器生成），您可以像这样遍历 JSON 对象以获取它们：

    Iterator<?> keys = json.keys();

    while(keys.hasNext()){
        String key = (String)keys.next();
        if (json.get(key) instanceof JSONObject ){
            // do something with the node referenced by the key
        }
    }
于 2013-07-09T17:23:01.623 回答
0

你必须使用 JsonReader：http: //developer.android.com/reference/android/util/JsonReader.html

如果输出的格式是您在此处描述的，您可以对正在检索的 JSON 对象做一些假设。例如，如果对象名称与“error”不同并且以“S”开头，您可以假设这是您想要的对象。

在您的情况下，您需要像这样解析代码：

reader.beginObject();
while(reader.hasNext()){
    String name = reader.nextName();
    if(name.startsWith("S")){
        reader.beginObject()
        //do your stuff
        reader.endObject();
    }
    else
        reader.skipValue()
}
reader.endObject();
于 2013-07-09T17:20:14.210 回答
0

在您的情况下，数组中有三个 json 对象。

为什么不将数组的值存储在哈希映射（或任何键值类型）中。

现在，您的每个哈希图都将包含一个键和一个值。值是你的 json，它

你可以再次解析它。

看看这个类似的问题。

于 2013-07-09T17:20:38.303 回答