在 MSSQL TABLE 我有 3 列。
ID (IDENTITY), KeptValue(NVARCHAR), SPENT(MONEY).
我有多个KeptValue
重复的 s。我需要删除所有重复项并保留 1 个。但我需要保留花费最多的那个。
我创建了 2 个视图。重复保留值的列表VW_DUPLICATE1
。
在 MSSQL TABLE 我有 3 列。
ID (IDENTITY), KeptValue(NVARCHAR), SPENT(MONEY).
我有多个KeptValue
重复的 s。我需要删除所有重复项并保留 1 个。但我需要保留花费最多的那个。
我创建了 2 个视图。重复保留值的列表VW_DUPLICATE1
。
delete t1
from your_table t1
left join
(
select keptvalue, max(spent) as mSpent
from your_table
group by keptvalue
) t2 on t1.keptvalue = t2.keptvalue and t1.spent = t2.mSpent
where t2.mSpent is null
尝试这个
DELETE FROM tbl WHERE Id IN (
SELECT Id FROM (
SELECT
Id
,ROW_NUMBER() OVER (PARTITION BY KeptValue ORDER BY SPENT DESC) AS [ItemNumber]
FROM
tbl
) a WHERE ItemNumber > 1
)
您可以使用此查询通过特定KepValue
保留最高删除SPENT
。
DELETE FROM your_table WHERE SPENT < (SELECT MAX(SPENT) FROM your_table WHERE KeptValue='your_value') AND KeptValue='your_value'
尝试这个
Create table #temp ( ID int, KeptValue NVARCHAR(20) , SPENT numeric(18,3))
INSERT INTO #temp select 1,'KeptValue1', 20
INSERT INTO #temp select 2,'KeptValue1', 21
INSERT INTO #temp select 3,'KeptValue2', 22
INSERT INTO #temp select 4,'KeptValue2', 20
INSERT INTO #temp select 5,'KeptValue2', 20
INSERT INTO #temp select 6,'KeptValue3', 20
INSERT INTO #temp select 7,'KeptValue3', 23
INSERT INTO #temp select 8,'KeptValue3', 24
INSERT INTO #temp select 9,'KeptValue4', 28
INSERT INTO #temp select 10,'KeptValue4', 23
INSERT INTO #temp select 11,'KeptValue5', 24
INSERT INTO #temp select 12,'KeptValue6', 28
select * FROM #temp
DELETE
FROM #temp
WHERE ID
in(
select ID from
(SELECT Id, (ROW_NUMBER() OVER(PARTITION BY KeptValue order by SPENT desc)) as R
from #temp
) as RowsNm
WHERE R >1)
select * from #temp
drop table #temp
您可以通过在 Spent 上执行group by
KeptValue 和max
聚合来实现此目的