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我正在关注http://www.raywenderlich.com/13511/how-to-create-an-app-like-instagram-with-a-web-service-backend-part-12#comments教程。我打开了一个 XAMPP 服务器，当我打开时http://localhost/iReporter因为 iReporter 是文件夹的名称，错误是

解析错误：语法错误，第 5 行 /Applications/XAMPP/xamppfiles/htdocs/iReporter/lib.php 中的意外 T_STRING

这是 lib.php 的代码：

<?

//setup db connection

$link = mysqli_connect("localhost","root","")

mysqli_select_db($link, "iReport");

//executes a given sql query with the params and returns an array as result function
query() {

global $link;

$debug = false;

//get the sql query
$args = func_get_args();
$sql = array_shift($args);
//secure the input
for ($i=0;$i<count($args);$i++) {
    $args[$i] = urldecode($args[$i]);
    $args[$i] = mysqli_real_escape_string($link, $args[$i]);
}

//build the final query
$sql = vsprintf($sql, $args);

if ($debug) print $sql;

//execute and fetch the results
$result = mysqli_query($link, $sql);
if (mysqli_errno($link)==0 && $result) {

    $rows = array();
    if ($result!==true)
    while ($d = mysqli_fetch_assoc($result)) {
        array_push($rows,$d);
    }

    //return json
    return array('result'=>$rows);

} else {

    //error
    return array('error'=>'Database error');
}

}

//loads up the source image, resizes it and saves with -thumb in the file name function thumb($srcFile, $sideInPx) {

$image = imagecreatefromjpeg($srcFile);

$width = imagesx($image);

$height = imagesy($image);

$thumb = imagecreatetruecolor($sideInPx, $sideInPx);

imagecopyresized($thumb,$image,0,0,0,0,$sideInPx,$sideInPx,$width,$height);

imagejpeg($thumb, str_replace(".jpg","-thumb.jpg",$srcFile), 85);

imagedestroy($thumb); imagedestroy($image); }

?>

我的问题是什么？请帮忙！

- 编辑 -

现在它说当我更改为时第 35 行出现 $link = mysqli_connect("localhost","root","")错误 $link = mysqli_connect("localhost","root","");！

4

1 回答 1

1

有一个缺失的“;” 在行中

$link = mysqli_connect("localhost","root","")

并且必须是

$link = mysqli_connect("localhost","root","");
于 2013-07-09T00:40:22.960 回答