0

鉴于此图：

http://console.neo4j.org/r/g3j3xo

我正在尝试返回所有影响同一 schoolTypeClass 中的哲学家的哲学家。首先，我将展示运行良好的查询。问题查询在帖子的底部。

这是上面链接中的默认查询。我的目的是证明数据是存在的。也就是说，亚里士多德和柏拉图都共享 SchoolTypeClass '运动'

MATCH p1:Philosopher-[:MEMBER_OF]->s1:School-[:TYPE_OF]->st1:SchoolType-[:SUBCLASS_OF]->stc1:SchoolTypeClass
   WHERE  stc1.name = 'movement'
   RETURN p1.name as p1Name, s1.name as s1Name, st1.name as st1Name, stc1.name as stc1Name

这是一个运行良好的查询。它与不起作用的查询非常相似。它显示了在同一 schoolType 而不是 schoolTypeClass 中影响哲学家的哲学家

MATCH st2:SchoolType<-[:TYPE_OF]-s2:School<-[:MEMBER_OF]-p2:Philosopher<-[:INFLUENCES]-p1:Philosopher-[:MEMBER_OF]->s1:School-[:TYPE_OF]->st1:SchoolType
   WHERE  st2 = st1
   RETURN p1.name as p1Name, s1.name as s1Name, st1.name as st1Name, p2.name as p2Name, s2.name as s2Name, st2.name as st2Name

问题查询不返回任何内容。如何在同一个 schoolTypeClass 中获得影响哲学家的哲学家？

MATCH stc2:SchoolTypeClass<-[:SUBCLASS_OF]-st2:SchoolType<-[:TYPE_OF]-s2:School<-[:MEMBER_OF]-p2:Philosopher<-[:INFLUENCES]-p1:Philosopher-[:MEMBER_OF]->s1:School-[:TYPE_OF]->st1:SchoolType-[:SUBCLASS_OF]->stc1:SchoolTypeClass
   WHERE stc1 = stc2
   RETURN p1.name as p1Name, s1.name as s1Name, st1.name as st1Name, stc1.name as stc1Name, p2.name as p2Name, s2.name as s2Name, st2.name as st2Name, stc2.name as stc2Name
4

1 回答 1

0

您不能在同一个 MATCH (stc1/2) 中拥有两次具有不同名称的同一个节点。

MATCH p=s2:School<-[:MEMBER_OF]-p2:Philosopher
        <-[:INFLUENCES]-p1:Philosopher-[:MEMBER_OF]->s1:School
        -[:TYPE_OF]->st1:SchoolType-[:SUBCLASS_OF]->stc:SchoolTypeClass 
WHERE (stc)<-[:SUBCLASS_OF]-(:SchoolType)<-[:TYPE_OF]-s2 
RETURN p1.name AS p1Name, s1.name AS s1Name, st1.name AS st1Name, 
       stc.name AS stcName, p2.name AS p2Name, s2.name AS s2Name, p

所以你宁愿在比赛后检查。

http://console.neo4j.org/r/t6lj05

于 2013-07-08T22:27:05.013 回答