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所以我一直致力于网络服务。但是我遇到了这个问题，我不知道如何在我的列表视图中显示图像。我从 JSON 数组中获取数据。下面是我的代码：

  // url to make request
private static String url = "http://alyssayango.x10.mx/";

private static final String TAG_TYPE = "movie_type";
private static final String TAG_NAME = "movie_name";
private static final String TAG_LENGTH = "movie_length";
private static final String TAG_SCHEDULES = "movie_schedules";
private static final String TAG_CINEMA = "movie_cinema_number";
private static final String TAG_URL = "movie_image_url";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    String readMovieSchedules = readMovieSchedules();

    // Hashmap for ListView
    ArrayList<HashMap<String, String>> movieList = new ArrayList<HashMap<String, String>>();

    try {
      JSONArray jsonArray = new JSONArray(readMovieSchedules);
      Log.i(MainActivity.class.getName(),
          "Number of entries " + jsonArray.length());
      for (int i = 0; i < jsonArray.length(); i++) {
        JSONObject jsonObject = jsonArray.getJSONObject(i);
        Log.i(MainActivity.class.getName(), jsonObject.getString("movie_name"));

        // Storing each json item in variable
        String name = jsonObject.getString(TAG_NAME);
        String type = jsonObject.getString(TAG_TYPE);
        String length = jsonObject.getString(TAG_LENGTH);
        String cinema = jsonObject.getString(TAG_CINEMA);
        String schedules = jsonObject.getString(TAG_SCHEDULES);
        String url = jsonObject.getString(TAG_URL);

        // creating new HashMap
        HashMap<String, String> map = new HashMap<String, String>();

        // adding each child node to HashMap key => value
        map.put(TAG_NAME, name);
        map.put(TAG_TYPE, type);
        map.put(TAG_LENGTH, length);
        map.put(TAG_CINEMA, cinema);
        map.put(TAG_SCHEDULES, schedules);
        map.put(TAG_URL, url);

        // adding HashList to ArrayList
        movieList.add(map);

        String strURL = TAG_URL.replaceAll(" ", "%20");

        /**
         * Updating parsed JSON data into ListView
         * */
        ListAdapter adapter = new SimpleAdapter(this, movieList,
                R.layout.list_item,
                new String[] { strURL, TAG_NAME, TAG_CINEMA, TAG_SCHEDULES }, 
                new int[] { R.id.image, R.id.name, R.id.cinema, R.id.schedules });

        setListAdapter(adapter);
        // selecting single ListView item
        ListView lv = getListView();

结果只显示文本而不是图像，我的 logcat 抛出：resolveURi failed on bad bitmap uri: http://www.sample.com/file.jpg

非常感谢您的帮助。我是安卓新手。

4

1 回答 1

1

使用 ImageLoader 、 Utils 、 FileCache 和 MemoryCache.java 文件并在您的适配器中编写此代码

ImageLoader iv_loader = new ImageLoader(main_activity.context); iv_loader.DisplayImage(msgs.Image,image); return v; msgs 是获取点击项位置的类名变量。image 是图像视图名称。

我希望并确信这段代码可以正常工作

于 2013-07-23T03:39:10.113 回答