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我习惯于在 mysql 中使用嵌套集并检索单个路径，我通常会使用以下内容：

SELECT node.treeID,
       node.name,
       node.lft,
       node.rgt,
       (COUNT(parent.name) - (sub_tree.depth + 1)) AS depth
FROM docsTree AS node,
     docsTree AS parent,
     docsTree AS sub_parent,

  ( SELECT node.name,
           (COUNT(parent.name) - 1) AS depth
   FROM docsTree AS node,
        docsTree AS parent
   WHERE node.lft BETWEEN parent.lft AND parent.rgt
     AND node.treeID = :requestedNode
   GROUP BY node.treeID,
            node.name,
            node.lft,
            node.rgt
   ORDER BY node.lft)AS sub_tree
WHERE node.lft BETWEEN parent.lft AND parent.rgt
  AND node.lft BETWEEN sub_parent.lft AND sub_parent.rgt
  AND sub_parent.name = sub_tree.name
GROUP BY node.treeID,
         node.name,
         node.lft,
         node.rgt HAVING depth = 1
ORDER BY node.lft

现在我需要在 db2 中做同样的事情，但上面的查询给了我以下错误：

错误：SELECT 或 HAVING 子句中的列引用无效，因为它不是分组列；或者 GROUP BY 子句中的列引用无效。

[SQL0122] SELECT 列表中的列深度或表达式无效。错误代码：-122

如何从 db2 返回嵌套的设置路径？

4

1 回答 1

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在最后一个 group by 中，尝试使用

GROUP BY node.treeID,
     node.name,
     node.lft,
     node.rgt HAVING (COUNT(parent.name) - (sub_tree.depth + 1)) = 1
于 2013-07-08T15:15:53.157 回答