我在quoted-printable中有以下消息正文:
=D0=9E=D1=82=D0=B2=D0=B5=D1=82 1 =D0=BD=D0=B0 test 05<br> ------------- <br=
><meta http-equiv=3D"Content-Type" content=3D"text/html; charset=3Dus-ascii=
"><meta name=3D"Generator" content=3D"Microsoft Word 14 (filtered medium)">=
<!--[if gte mso 9]><xml>
<o:shapedefaults v:ext=3D"edit" spidmax=3D"1026" />
</xml><![endif]--><!--[if gte mso 9]><xml>
<o:shapelayout v:ext=3D"edit">
<o:idmap v:ext=3D"edit" data=3D"1" />
</o:shapelayout></xml><![endif]--><div class=3D"WordSection1"><p class=3D"M=
soNormal"><span lang=3D"EN-US">Test 04<o:p></o:p></span></p></div>
上面的代码被 OpenPop 正确解码。但是当我将此字符串设置为 HTMLBody 时,它变得不正确(我看到以下内容: Nrber 1 m` test 05 ------------- Test 04 )
rdoMessage.HTMLBody = decodedBody;
我还观察到,如果我执行以下操作,它会正确显示:
rdoMessage.Body = decodedBody;
rdoMessage.HTMLBody = decodedBody;
什么会导致这种行为?这两个属性如何相互影响?