我正在开发一个我想在我的朋友圈中使用的应用程序,我不想在 google play 上发布应用程序。我可以通过将我的应用程序保持在草稿模式来使用 GCM 服务吗?
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1112 次
3 回答
2
是的,你可以这样做,我在我的应用程序中集成了 GCM。
您只需要创建和托管您自己的服务器,该服务器将充当第三方服务器,用于注册设备并向 GCM 服务器发送消息。
您可以从必须分别在客户端和服务器上使用的 Google 控制台获取发件人密钥和 API 密钥。
于 2013-07-08T08:56:11.373 回答
1
你可以这样做..
static void register(final Context context, String name, String email, final String regId) {
//indented code
Log.i(TAG, "registering device (regId = " + regId + ")");
String serverUrl = SERVER_URL;
Map<String, String> params = new HashMap<String, String>();
params.put("regId", regId);
params.put("name", name);
params.put("email", email);
long backoff = BACKOFF_MILLI_SECONDS + random.nextInt(1000);
// Once GCM returns a registration id, we need to register on our server
// As the server might be down, we will retry it a couple
// times.
for (int i = 1; i <= MAX_ATTEMPTS; i++) {
Log.d(TAG, "Attempt #" + i + " to register");
try {
displayMessage(context, context.getString(
R.string.server_registering, i, MAX_ATTEMPTS));
post(serverUrl, params);
GCMRegistrar.setRegisteredOnServer(context, true);
String message = context.getString(R.string.server_registered);
CommonUtilities.displayMessage(context, message);
return;
} catch (IOException e) {
// Here we are simplifying and retrying on any error; in a real
// application, it should retry only on unrecoverable errors
// (like HTTP error code 503).
Log.e(TAG, "Failed to register on attempt " + i + ":" + e);
if (i == MAX_ATTEMPTS) {
break;
}
try {
Log.d(TAG, "Sleeping for " + backoff + " ms before retry");
Thread.sleep(backoff);
} catch (InterruptedException e1) {
// Activity finished before we complete - exit.
Log.d(TAG, "Thread interrupted: abort remaining retries!");
Thread.currentThread().interrupt();
return;
}
// increase backoff exponentially
backoff *= 2;
}
}
String message = context.getString(R.string.server_register_error,
MAX_ATTEMPTS);
CommonUtilities.displayMessage(context, message);
}
/**
* Unregister this account/device pair within the server.
*/
static void unregister(final Context context, final String regId) {
Log.i(TAG, "unregistering device (regId = " + regId + ")");
String serverUrl = SERVER_URL + "/unregister";
Map<String, String> params = new HashMap<String, String>();
params.put("regId", regId);
try {
post(serverUrl, params);
GCMRegistrar.setRegisteredOnServer(context, false);
String message = context.getString(R.string.server_unregistered);
CommonUtilities.displayMessage(context, message);
} catch (IOException e) {
// At this point the device is unregistered from GCM, but still
// registered in the server.
// We could try to unregister again, but it is not necessary:
// if the server tries to send a message to the device, it will get
// a "NotRegistered" error message and should unregister the device.
String message = context.getString(R.string.server_unregister_error,
e.getMessage());
CommonUtilities.displayMessage(context, message);
}
}
于 2013-07-08T08:42:38.617 回答
1
是的,您可以在不发布应用程序的情况下使用它。正如纳尔吉斯所说,您需要创建自己的服务器。
这里有一个很棒的教程,希望对您有所帮助。
于 2013-07-08T09:24:59.017 回答