php - 连接SQL

Question

这是我的代码

$this->db->select('*, CONCAT(left(card_id, 1 ), right(card_id, 6 )) AS character_id', FALSE);

错误：遇到错误

Unknown column '1' in 'field list'

请在这件事上给予我帮助！！！

Answer 1

您似乎忘记指定您的表名。

请将 [tablename] 替换为您的表名：

$this->db->query('SELECT *, CONCAT(left(card_id, 1 ), right(card_id, 6 )) AS character_id FROM [tablename]');

或者：

$this->db->select("*, CONCAT(left(card_id, 1 ), right(card_id, 6 )) AS character_id");
$this->db->from("[tablename]");
$res = $this->db->get();

Answer 2

试试这个方法

$this->db->select("*, CONCAT(left(card_id, 1 ), right(card_id, 6 )) AS character_id",FALSE);
$this->db->from("table");
$query = $this->db->get();
return $query;