mysql - 将值的总和与差异表中相同 ID 的其他值进行比较

Question

mysql我的脚本有问题。

我有 2 张桌子，我想在另一张桌子上比较我invoiceAmount的。paymentAmount情况是：一张发票可以有很多付款，我想invoiceAmount (table A)与paymentAmount (table B).

我已经用paymentAmount相同的 invoiceID 计算加入了它，我的问题是如何比较它（所有行的两个表中相同 invoiceID 的总和）paymentAmount(table B)？invoiceAmount (table A)真的需要你们的帮助。。

我的脚本是：

SELECT invoice.InvoiceID, invoice.InvoiceAmount, pays.InvoiceID, sum(pays.PaymentAmount) as pays, invoice.InvoiceDate 
FROM `payment from customer` as pays
JOIN invoice ON(pays.InvoiceID=invoice.InvoiceID)
WHERE pays.InvoiceID in (
    SELECT InvoiceID 
    FROM `payment from customer`
    GROUP BY InvoiceID
    HAVING count(*) > 1)
GROUP BY pays.InvoiceID

Answer 1

SELECT * 
FROM (select invoice.InvoiceID, 
             invoice.InvoiceAmount, 
             pays.InvoiceID, 
             pays.PaymentAmount as pays, 
             invoice.InvoiceDate ,
             (select sum(a.PaymentAmount) 
                from `payment from customer` a 
               where a.InvoiceID = invoice.InvoiceID) totalPays
        from `payment from customer` as pays JOIN invoice 
          ON (pays.InvoiceID=invoice.InvoiceID) ) temp
where InvoiceDate > totalPays

Answer 2

在结果表中添加一个字段，您可以在其中计算仍需支付的总和。

例如，如果您想要一个仍有余额要支付的发票列表：

  SELECT invoice.InvoiceID,
         invoice.InvoiceAmount,
         pays.InvoiceID,
         sum(pays.PaymentAmount) AS pays,
         sum(pays.PaymentAmount) - invoice.InvoiceAmount AS StillToPay
         invoice.InvoiceDate
    FROM `payment from customer` AS pays
         JOIN invoice ON pays.InvoiceID = invoice.InvoiceID
   WHERE pays.InvoiceID IN (   SELECT InvoiceID FROM `payment from customer`
                             GROUP BY InvoiceID
                               HAVING count(*) > 1 )
     AND StillToPay > 0
GROUP BY pays.InvoiceID

未经测试的查询！