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我无法填充我正在尝试绘制的这个图案的内部(红色的..)背景上的黑色形状只是一个虚拟 jpeg

http://s8.postimg.org/7rsho4mr9/shape.png

var stage = new createjs.Stage("shape");
stage.enableMouseOver();
stage.mouseMoveOutside = true;
createjs.Touch.enable(stage);

var width = $('#shape').width(),
border_width = 3,
part_border = 2 * border_width,
part_width = width / parts_num,
shape_width = part_width-part_border;

var container = new createjs.Container();

var shape = new createjs.Shape();
shape.x = 17;
shape.y = 0;
shape.name = 'morin1';
shape.graphics.setStrokeStyle(part_border);
shape.graphics.beginStroke("#f00");
shape.graphics.beginFill("yellow");


//top line
shape.graphics.moveTo(0, 0);
shape.graphics.lineTo(shape_width,0);

//bottom line
shape.graphics.moveTo(0, 174);
shape.graphics.lineTo(shape_width,174);

//left line - top part
shape.graphics.moveTo(0, 0);
shape.graphics.bezierCurveTo(30, 21, 13, 60, 0, 90);

//left line - bottom part
shape.graphics.bezierCurveTo(-18, 120, -24, 140, 0, 178);

//right line - top part
shape.graphics.moveTo(shape_width, 0);
shape.graphics.bezierCurveTo(shape_width+30, 21, shape_width+13, 60, shape_width+0, 90);

//right line - bottom part
shape.graphics.bezierCurveTo(shape_width-18, 120, shape_width-24, 140, shape_width, 178);
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1 回答 1

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问题是我经常使用 moveTo,当我更改代码并在不使用 moveTo 的情况下绘制形状时,效果很好。

于 2013-07-07T13:29:03.793 回答