我一直在谷歌搜索和测试这个问题很长一段时间，但找不到答案。
我有一个网站，服务器调查由管理员上传。这些调查属于调查周期，答案属于答案。
class Answering < ActiveRecord::Base
has_many :answers
accepts_nested_attributes_for :answers, :allow_destroy => true
has_many :alternative_answers, :through => :answers
accepts_nested_attributes_for :alternative_answers, :allow_destroy => true
validate :check_for_fail
end
class Answer < ActiveRecord::Base
belongs_to :answering
has_many :alternative_answers, :dependent => :destroy
accepts_nested_attributes_for :alternative_answers
控制器对于嵌套对象来说是非常基础的
def new
if @surveycycle.nil?
@surveycycle = Surveycycle.find(params[:surveycycle_id])
if !params[:game_id].nil?
@game = Game.find(params[:game_id])
@game_id = @game.id
else
@game_id = nil
end
if @answering.nil?
@answering = Answering.new()
@answering.answers.build
@answering.answers.each do |x|
x.alternative_answers.build
end
end
@surveys = []
for survey in @surveycycle.surveys
@surveys << Survey.find(survey.id, :include => [:sub_surveys, :questions])
end
end
end
if 中的所有内容，因为 render :action => "new" 似乎使用了 create 中的对象。
def create
@surveycycle = Surveycycle.find(params["answering"].delete(:surveycycle_id).to_i)
if !params[:answering][:game_id].nil? and !params[:answering][:game_id].empty?
@game = Game.find(params[:answering][:game_id])
@game_id = @game.id
else
@game = nil
@game_id = nil
end
#If user is not logged in, use a fakeuser
if !logged_in?
@fakeuser = Fakeuser.new
@fakeuser.save
@answering = Answering.new(params[:answering].merge({:fakeuser_id => @fakeuser.id}))
else
@answering = Answering.new(params[:answering])
end
@surveys = []
for survey in @surveycycle.surveys
@surveys << Survey.find(survey.id, :include => [:sub_surveys, :questions])
end
#Dummy version for debugging
render :action => "new"
我用这样的部分处理的视图
新的.html.erb
<% form_for :answering, @answering, :url => {:action => "create"}, :html => {:method => :post} do |all_f| %>
<%= all_f.error_messages %>
<%= all_f.hidden_field :game_id, :value => @game_id %>
<% if logged_in? %>
<%= all_f.hidden_field :user_id, :value => current_user.id %>
<% end %>
<%= all_f.hidden_field :surveycycle_id, :value => @surveycycle.id %>
<% @surveys.each_with_index do |survey, survey_index| %>
<div id="whole_survey">
<% survey.sub_surveys.each_with_index do |sub_survey, sub_survey_index| %>
<div id="sub_survey">
<b><div id="sub_survey_name"><%= sub_survey.name %> </div></b><br>
<% sub_survey.questions.each_with_index do |question, question_index| %>
<table>
<div id="question">
<% all_f.fields_for :answers do |f| %>
<%= render :partial => 'answer', :locals => {:f => f, :question => question} %>
<% end %>
</div>
</table>
<% end %>
</div>
<% end %>
</div>
<% end %>
<%= all_f.submit t('answer') %>
<% end %>
视图部分中的内容非常臃肿，因为问题可能来自各种各样
现在关于这个问题！当用户提交此表单时，它显然会再次呈现表单（我强制应答控制器 create-action 'render :action => "new" 以调试我一直遇到的这个问题）。不是再次获得相同的表格，而是将问题呈现 x 次，其中 8 个问题 x 为 9。例如，对于 8 个问题的短调查周期，在第一次提交后，每个问题显示 9 次。查看页面源码，第一次提交时输入id：s从0到8，然后0到80，然后突然0到728。
我将说明这一点：
..surveystuff..
Q: I was immersed in the game
Very immersed o o x o o o o not at all immersed
..surveystuff..
用户点击提交后，变成：
..surveystuff..
Q: I was immersed in the game
Q: I was immersed in the game
Q: I was immersed in the game
Q: I was immersed in the game
Q: I was immersed in the game
Q: I was immersed in the game
Q: I was immersed in the game
Q: I was immersed in the game
Q: I was immersed in the game
Q: I was immersed in the game
Very immersed o o x o o o o not at all immersed
Very immersed o o o o o o o not at all immersed
Very immersed o o o o o o o not at all immersed
Very immersed o o o o o o o not at all immersed
Very immersed o o o o o o o not at all immersed
Very immersed o o o o o o o not at all immersed
Very immersed o o o o o o o not at all immersed
Very immersed o o o o o o o not at all immersed
Very immersed o o o o o o o not at all immersed
Very immersed o o o o o o o not at all immersed
..surveystuff..
这可能是一个错误或什么，还是我做错了什么？
如果需要，我可以发布更多内容。