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我试图根据向量中指针的派生类型调用重载函数。

我有一个基类 Fruit，并创建一个 shared_ptr 向量。然后我将后代的共享指针推送到向量中。到目前为止，一切都很好（问题出现在我添加代码以打印元素之后）。

接下来，我想遍历容器，为每个水果调用适当的 Print 函数。我收到编译错误： 

# g++ -I/cygdrive/c/Program\ Files/boost/boost_1_52_0 -o main.exe main.cpp
main.cpp: In function `int main()':
main.cpp:80: error: no matching function for call to `Print_via_ptr(const boost::shared_ptr<Fruit>&)'
main.cpp:57: note: candidates are: void Print_via_ptr(boost::shared_ptr<Apple>)
main.cpp:58: note:                 void Print_via_ptr(boost::shared_ptr<Orange>)
main.cpp:59: note:                 void Print_via_ptr(boost::shared_ptr<Strawberry>)
main.cpp:95: error: no matching function for call to `Print(Fruit&)'
main.cpp:53: note: candidates are: void Print(const Apple&)
main.cpp:54: note:                 void Print(const Orange&)
main.cpp:55: note:                 void Print(const Strawberry&)

这是代码： 

#include <iostream>
#include <string>
#include <cstdlib>
#include <vector>
#include "boost/shared_ptr.hpp"

using std::cout;
using std::cin;
using std::endl;


struct Fruit
{
    virtual const std::string&      who_am_i(void) const = 0;
};


struct Apple
    : public Fruit
{
    const std::string& who_am_i(void) const
        {
            static const std::string name = "Apple";
            return name;
        }
};


struct Orange
    : public Fruit
{
    const std::string& who_am_i(void) const
        {
            static const std::string name = "Orange";
            return name;
        }
};


struct Strawberry
    : public Fruit
{
    const std::string& who_am_i(void) const
        {
            static const std::string name = "Strawberry";
            return name;
        }
};


void Pause(void);

void Print(const Apple& a);
void Print(const Orange& o);
void Print(const Strawberry& s);

void Print_via_ptr(boost::shared_ptr<Apple> p_a);
void Print_via_ptr(boost::shared_ptr<Orange> p_o);
void Print_via_ptr(boost::shared_ptr<Strawberry> p_s);


int main(void)
{
    std::vector<boost::shared_ptr<Fruit> >  basket;
    boost::shared_ptr<Apple>        p_apple(new Apple);
    boost::shared_ptr<Orange>       p_orange(new Orange);
    boost::shared_ptr<Strawberry>   p_strawberry(new Strawberry);

    // Put fruit into basket.
    basket.push_back(p_apple);
    basket.push_back(p_orange);
    basket.push_back(p_strawberry);

    // Display the basket of fruit shared_ptr
    cout << "Basket contents:\n";
    for (std::vector<boost::shared_ptr<Fruit> >::const_iterator iter = basket.begin();
         iter != basket.end();
         ++iter)
    {
        Print_via_ptr(*iter); // Line 80
    }

    //  Create bowl of fruit pointers
    std::vector<Fruit *>    bowl;
    bowl.push_back(new Apple);
    bowl.push_back(new Orange);
    bowl.push_back(new Strawberry);

    //  Print the fruit.
    std::vector<Fruit *>::const_iterator bowl_iter;
    for (bowl_iter = bowl.begin();
         bowl_iter != bowl.end();
         ++bowl_iter)
    {
        Print(**bowl_iter); // Line 95
    }

    Pause();

    return EXIT_SUCCESS;
}


void
Pause(void)
{
    cout << "Paused. Press Enter to continue.\n";
    cin.ignore(10000, '\n');
}


void
Print(const Apple& a)
{
    cout << a.who_am_i() << endl;
}


void
Print(const Orange& o)
{
    cout << o.who_am_i() << endl;
}


void
Print(const Strawberry& s)
{
    cout << s.who_am_i() << endl;
}


void
Print_via_ptr(boost::shared_ptr<Apple> p_a)
{
    cout << p_a->who_am_i() << endl;
}


void
Print_via_ptr(boost::shared_ptr<Orange> p_o)
{
    cout << p_o->who_am_i() << endl;
}


void
Print_via_ptr(boost::shared_ptr<Strawberry> p_s)
{
    cout << p_s->who_am_i() << endl;
}

我在 Windows Vista 上，在 Cygwin 下使用 g++：

# g++ --version
g++ (GCC) 3.4.4 (cygming special, gdc 0.12, using dmd 0.125)

我想Print_via_ptr(boost::shared_ptr<Apple>)在调用时被调用： 

Print_via_ptr(bowl[0]);
4

1 回答 1

1

多态分派是通过基指针或引用类型完成的，它不会自动转换为派生指针/引用类型。

std::vector<boost::shared_ptr<Fruit> >  basket;
boost::shared_ptr<Apple>    p_apple(new Apple);
basket.push_back(p_apple);

当你调用push_back时，对象被存储为boost::shared_ptr<Fruit>notboost::shared_ptr<Apple>

他们只能被

void Print_via_ptr(const boost::shared_ptr<Fruit> p_a);
                                           ^^^^^

您的原始指针函数也存在同样的问题。

或者您可以使用模板为您生成呼叫，但这可能不是您的目的。

template<typename T>
void Print_via_ptr(T p_o)
{
    std::cout << p_o->who_am_i() << std::endl;
}
于 2013-07-07T03:16:17.450 回答