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有谁知道我可以使用 PHP 从 MySql DB 中的 2 个表中获取数据的方法?我的 android 应用程序允许用户将商品放入购物车(MySql 中的表格)。当用户点击应用程序中的购物车按钮时,它会加载“购物车活动”并加载一个列表视图,其中包含他们基于“会话 ID”或“客户 ID”添加到购物车中的所有内容(如果他们已登录) . 我现在要做的是将商品添加到购物车时,我会捕获产品 ID、产品名称和图像 URL、数量和价格。它工作得很好而且很快。我想要做的是因为产品名称、图片 url 和价格已经在“产品表”中我想做同样的事情但是当用户将一个项目添加到他们的购物车时只捕获产品 ID 和会话 ID .

这是我的 PHP 脚本:

if($The_Function=="LOAD_CART"){
    $response = array();

    require_once __DIR__ . '/db_connect.php';

    $con = new DB_CONNECT();

    $user_session = $_GET['session'];
    $user_item_status = $_GET['status'];
    $order_total = 0.00;
    $result = mysql_query("SELECT * FROM shopping_cart WHERE SessionID LIKE '$user_session' AND Status LIKE '$user_item_status'");

    if(!empty($result)){
        if (mysql_num_rows($result) > 0) {
            $response["cart_contents"] = array();
            //$result = mysql_fetch_array($result);
            while ($row = mysql_fetch_array($result)) {
                $myItems = array();

                $myItems["product_id"] = $row["PID"];
                $myItems["product_name"] = $row["Item"];
                $myItems["product_price"] = $row["Price"];
                $myItems["product_qty"] = $row["Qty"];
                $myItems["image_url"] = $row["URL"];
                $myItems["line_id"] = $row["ItemCount"];
                $line_total = $row["Price"] * $row["Qty"];
                $order_total = $order_total + $line_total;
                array_push($response["cart_contents"], $myItems);
            }
            // success
            $response["success"] = 1;
            $response["order_total"] = $order_total;
            // user node
            //  $response["products"] = array();
            // echoing JSON response
            echo json_encode($response);
        } else {
            // no product found
            $response["success"] = 0;
            $response["message"] = "No product found";

            // echo no users JSON
            echo json_encode($response);
        }
    } else {
        // no product found
        $response["success"] = 0;
        $response["message"] = "No product found";

        // echo no users JSON
        echo json_encode($response);
    }
}

这是我想要做的。此代码不起作用。

if($The_Function=="LOAD_CART2"){
    $response = array();

    require_once __DIR__ . '/db_connect.php';

    $con = new DB_CONNECT();

    $user_session = $_GET['session'];
    $user_item_status = $_GET['status'];
    $order_total = 0.00;
    $result = mysql_query("SELECT * FROM shopping_cart WHERE SessionID LIKE '$user_session' AND Status LIKE '$user_item_status'");

    if(!empty($result)){
        if (mysql_num_rows($result) > 0) {
            $response["cart_contents"] = array();
            //$result = mysql_fetch_array($result);
            while ($row = mysql_fetch_array($result)) {
                $line_total = $row["Price"] * $row["Qty"];
                $line_ID = $row["ItemCount"];
                $Quantity = $row["Qty"];
                $Prod_ID = $row["PID"];


                $result2 = mysql_query("SELECT * FROM products WHERE pid LIKE '$Prod_ID'");
                $myItems = array();
                $theItem=$row["name"];
                $thePrice=$row["price"];
                $theImage=$row["prod_image"];

                $myItems["line_id"] = $line_ID;
                $myItems["product_qty"] = $Quantity;
                $myItems["product_id"] = $Prod_ID;
                $myItems["product_name"] = $theItem;
                $myItems["product_price"] = $thePrice;
                $myItems["image_url"] = $theImage;

                $order_total = $order_total + $line_total;
                array_push($response["cart_contents"], $myItems);
            }




            }
            // success
            $response["success"] = 1;
            $response["order_total"] = $order_total;
            // user node
            //  $response["products"] = array();
            // echoing JSON response
            echo json_encode($response);
        } else {
            // no product found
            $response["success"] = 0;
            $response["message"] = "No product found";

            // echo no users JSON
            echo json_encode($response);
        }
    } else {
        // no product found
        $response["success"] = 0;
        $response["message"] = "No product found";

        // echo no users JSON
        echo json_encode($response);
    }

这就是我刚刚尝试过的:

if($The_Function=="LOAD_CART2"){
    $response = array();

    require_once __DIR__ . '/db_connect.php';

    $con = new DB_CONNECT();

    $user_session = $_GET['session'];
    $user_item_status = $_GET['status'];
    $order_total = 0.00;

    $result = mysql_query("SELECT s.*, p.* FROM shopping_cart AS s LEFT JOIN products AS p ON p.pid = s.PID WHERE s.SessionID ='$user_session' AND s.Status = '$user_item_status'");

    if(!empty($result)){
        if (mysql_num_rows($result) > 0) {
            $response["cart_contents"] = array();
            //$result = mysql_fetch_array($result);
            while ($row = mysql_fetch_array($result)) {
                $myItems = array();
                //FROM shopping_cart Table
                $line_total = $row["Price"] * $row["Qty"];
                $myItems["line_id"] = $row["ItemCount"];
                $myItems["product_qty"] = $row["Qty"];
                $myItems["product_id"] = $row["PID"];

                //FROM product TABLE
                $myItems["product_name"]=$row["p.name"];
                $myItems["product_price"]=$row["p.price"];
                $myItems["image_url"]=$row["p.prod_image"];


            }

            $order_total = $order_total + $line_total;
            array_push($response["cart_contents"], $myItems);


            }
            // success
            $response["success"] = 1;
            $response["order_total"] = $order_total;
            // user node
            //  $response["products"] = array();
            // echoing JSON response
            echo json_encode($response);
        } else {
            // no product found
            $response["success"] = 0;
            $response["message"] = "No product found";

            // echo no users JSON
            echo json_encode($response);
        }
    } else {
        // no product found
        $response["success"] = 0;
        $response["message"] = "No product found";

        // echo no users JSON
        echo json_encode($response);
    }

我的方案:

products TABLE

pid|name|price|created_at|prod_image|description|catagory



shopping_cart TABLE

FirstName|LastName|OrderNumber|CustomerID|Email|Price|Qty|Status|URL|PID|SessionID|CustomerType|ItemCount
4

1 回答 1

0

您应该使用 LEFT JOIN 而不是对每个项目进行单独的查询。

就像是: "SELECT s.*, p.* FROM shopping_cart AS s LEFT JOIN products AS p ON p.pid = s.PID WHERE s.SessionID ='$user_session' AND s.Status = '$user_item_status'

假设小写的pid在products表中,大写的pid在shopping_card表中。

于 2013-07-06T01:46:08.373 回答