ios - 从 UITapGestureRecognizer 中排除子视图

Question

我有一个子视图和一个超级视图。超级视图附加了一个 UITapGestureRecognizer。

UIView *superview = [[UIView alloc] initWithFrame:CGRectMake:(0, 0, 320, 480);
UIView *subview = [[UIView alloc] initWithFrame:CGRectMake:(100, 100, 100, 100);
UIPanGestureRecognizer *recognizer = [[UIPanGestureRecognizer alloc] initWithTarget: self action: @selector(handleTap);
superview.userInteractionEnabled = YES;
subview.userInteractionEnabled = NO;
[superview addGestureRecognizer:recognizer];
[self addSubview:superview];
[superview addSubview:subview];

识别器也在子视图内触发，有没有办法从子视图中排除识别器？

我知道以前有人问过这个问题，但我没有找到一个好的答案。

Answer 1

您可以使用手势识别器委托来限制它可以识别触摸的区域，类似于此示例：

recognizer.delegate = self;
...

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch{
    CGPoint touchPoint = [touch locationInView:superview];
    return !CGRectContainsPoint(subview.frame, touchPoint);
}

请注意，您需要保留对父视图和子视图的引用（使它们成为实例变量？）才能在委托方法中使用它们

Answer 2

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch
{
    if(touch.view == yourSubview)
    {
        return NO;
    }
    else
    {
        return YES;
    }
}

谢谢：https ://stackoverflow.com/a/19603248/552488

Answer 3

对于 Swift 3，您可以view.contains(point)使用CGRectContainsPoint.

func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool {
    if yourSubview.frame.contains(touch.location(in: view)) {
        return false
    }
    return true
}