我正在使用 prettyPhoto API 使用以下代码手动打开灯箱:
api_images ['images/fullscreen/image1.jpg','images/fullscreen/image2.jpg','images/fullscreen/image3.jpg'];
api_titles = ['Title 1','Title 2','Title 3'];
api_descriptions = ['Description 1','Description 2','Description 3']
$.prettyPhoto.open(api_images,api_titles,api_descriptions);
我面临的问题是描述值是从 Wordpress 的 WYSIWYG 中提取的,并且代码很容易被随机的 html 标签、标点符号等破坏
<script type="text/javascript">
$(document).ready(function() {
$('#menu-item-1006').on('click', function(e) {
e.preventDefault();
var images = new Array();
var descriptions = new Array();
var titles = new Array();
<?php
$i = 0;
$images = new WP_Query(array('post_type' => 'clearance', 'showposts' => -1, 'order' => 'menu_order', 'orderby' => 'ASC'));
if ($images->have_posts()) : while ($images->have_posts()) : $images->the_post();
$featured = wp_get_attachment_image_src(get_post_thumbnail_id($post->ID), 'full');
?>
images[<?php echo $i; ?>] = '<?php echo $featured[0]; ?>';
titles[<?php echo $i; ?>] = '<?php the_title(); ?>'
descriptions[<?php echo $i; ?>] = '<?php echo get_the_content(); ?>';
<?php
$i++;
endwhile;
else:
?>
<?php endif; ?>
$.prettyPhoto.open(images, titles, descriptions);
})
});
</script>
如何过滤 get_the_content() 函数,使其输出无错误?谢谢!