python - 如何对数字字符串的python列表进行排序

Question

我正在尝试对包含数字的字符串列表进行排序

a = ["1099.0","9049.0"]
a.sort()
a
['1099.0', '9049.0']

b = ["949.0","1099.0"]
b.sort()    

b
['1099.0', '949.0']

a
['1099.0', '9049.0']

但是列表b是排序而不是列表a

Answer 1

您想根据float值（不是字符串值）进行排序，因此请尝试：

>>> b = ["949.0","1099.0"]
>>> b.sort(key=float)
>>> b
['949.0', '1099.0']

Answer 2

use a lambda inside sort to convert them to float and then sort properly:

a = sorted(a, key=lambda x: float(x))

so you will mantain them as strings but sorted by value and not lexicographically

Answer 3

如果有人在处理数字和扩展名，例如 0.png、1.png、10.png、2.png... 我们需要在扩展名之前检索和排序字符，因为这个扩展名不允许我们转换浮动名称：

myList = sorted(myList, key=lambda x: float(x[:-4]))

Answer 4

将它们转换为int或float什至decimal（因为它有尾随数字）

>>> b = [float(x) for x in b]
>>> b.sort()
>>> b
[949.0, 1099.0]