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我的程序中有轻微的内存泄漏，我不确定它是在我的分配中还是在内部 c 结构中。我使用的唯一 malloc 是这些：

results = (int*) malloc (instance_n * sizeof (int) );

instances = (char**) malloc (instance_n * sizeof (char*) );
for (i = 0; i < instance_n; i++) {
  instances[i] = (char*) malloc (1001 * sizeof (char) );
}

List_add (); (standard doubly linked list. Never gave me a problem)

我在同一个地方释放所有东西：

free (results);
List_clear (&dynamic);
for (i = 0; i < instance_n; i++) {
  free (instances[i]);
}
free (instances);

顺便说一句：List_clear =

Node* node = list->last;
if (node == NULL) return;

while (node->previous != NULL)
  {
    node = node->previous;
    free (node->next);
  }
free (list->first);

此外，我正在使用 timeval 和 FILE 结构（文件在方法结束时关闭）

我错过了什么吗？对我来说，这看起来就像我正在释放一切。我以前从未遇到过内存泄漏问题，所以我在调试它时很糟糕，但 Valgrind 一直指出这个内存泄漏：

==3180== HEAP SUMMARY:
==3180==     in use at exit: 62,951 bytes in 361 blocks
==3180==   total heap usage: 556 allocs, 195 frees, 115,749 bytes allocated
==3180== 
==3180== LEAK SUMMARY:
==3180==    definitely lost: 8,624 bytes in 14 blocks
==3180==    indirectly lost: 1,168 bytes in 5 blocks
==3180==      possibly lost: 4,925 bytes in 68 blocks
==3180==    still reachable: 48,234 bytes in 274 blocks
==3180==         suppressed: 0 bytes in 0 blocks
==3180== Rerun with --leak-check=full to see details of leaked memory
==3180==

我不禁注意到“14 块”部分，但我的代码中没有任何部分分配少于 20 个部分，并且 8624 字节是 4 字节的倍数，因此很可能是整数泄漏。

提前致谢

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1 回答 1

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我刚刚在 valgrind 上找到了这个子句：

==3821== WARNING: Support on MacOS 10.8 is experimental and mostly broken.
==3821== WARNING: Expect incorrect results, assertions and crashes.
==3821== WARNING: In particular, Memcheck on 32-bit programs will fail to
==3821== WARNING: detect any errors associated with heap-allocated data.

还有很多其他人在 MacOSX 10.8 上遇到了同样的 8624 字节泄漏，所以我猜这是误报。

于 2013-07-04T00:01:57.490 回答