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我在通过 FTP 将文件上传到我的 VPS（centos 6 64 位）时遇到了一些问题。我正在使用的 FTP 称为 Pure-FTPD，我正在尝试使用 Java 上传图像。我得到的错误代码是

java.net.MalformedURLException：对于输入字符串：“ VPS PASS HERE @9X.XXX.2XX.X8”在 java.net.URL.（未知来源）在 java.net.URL.（未知来源）在 java.net。 URL.(Unknown Source) at FtpUrlUpload.main(FtpUrlUpload.java:25) 原因：java.lang.NumberFormatException：对于输入字符串：“ VPS PASS HERE @9X.XXX.2XX.X8”在 java.lang.NumberFormatException。 forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.net.URLStreamHandler.parseURL(Unknown Source) ... 还有 4 个

这是我的完整代码。

import java.io.FileInputStream;
import java.io.IOException;
import java.io.OutputStream;
import java.net.URL;
import java.net.URLConnection;

public class FtpUrlUpload {

private static final int BUFFER_SIZE = 4096;

public static void main(String[] args) {
    String ftpUrl = "ftp://%s:%s@%s/%s;type=i";
    String host = "9X.XXX.2XX.X8";
    String user = "VPS USERNAME HERE";
    String pass = "VPS PASS HERE";
    String filePath = "C:\\Users\\user\\desktop\\Untitled.png";
    String uploadPath = "public_html/Untitled.png";

    ftpUrl = String.format(ftpUrl, user, pass, host, uploadPath);
    System.out.println("Upload URL: " + ftpUrl);

    try {
        URL url = new URL(ftpUrl);
        URLConnection conn = url.openConnection();
        OutputStream outputStream = conn.getOutputStream();
        FileInputStream inputStream = new FileInputStream(filePath);

        byte[] buffer = new byte[BUFFER_SIZE];
        int bytesRead = -1;
        while ((bytesRead = inputStream.read(buffer)) != -1) {
            outputStream.write(buffer, 0, bytesRead);
        }

        inputStream.close();
        outputStream.close();

        System.out.println("File uploaded");
    } catch (IOException ex) {
        ex.printStackTrace();
    }
}
}
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1 回答 1

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我假设这是由于用户名/密码中的空格没有正确编码？

尝试使用 URI.toURL()

http://docs.oracle.com/javase/6/docs/api/java/net/URI.html

于 2013-07-03T20:22:18.673 回答