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我有以下数据集:

Row   - Customer    - Renew Date     - Type of Renewal     - Days  
 1       - A        - June 10, 2010        - X                        
 2       - A        - May 01, 2011         - Y  
 3       - B        - Jan 05, 2010         - Y  
 4       - B        - Dec 10, 2010         - Z   
 5       - B        - Dec 10, 2011         - X    

有没有一种方法可以在查询生成器中设置条件,从第 2 行中为每个客户减去第 1 行,这样我就可以在客户续订会员资格后获得“天数”?
基本上,我需要帮助来减去查询生成器中的行。
请注意。

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1 回答 1

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如果您编写数据步,这并不难。我不知道它在查询生成器中很容易完成。

data have;
informat renew_date ANYDTDTE.;
format renew_date DATE9.;
infile datalines dlm='-';
input Row Customer $ Renew_Date  Renewal_Type $;
datalines;
 1       - A        - June 10, 2010        - X                        
 2       - A        - May 01, 2011         - Y  
 3       - B        - Jan 05, 2010         - Y  
 4       - B        - Dec 10, 2010         - Z   
 5       - B        - Dec 10, 2011         - X    
 ;;;;
 run;

 data want;
 set have;
 by customer;
 retain prev_days;  *retain the value of prev_days from one row to the next;
 if first.customer then days_since=0; *initialize days_since to zero for each customer's first record;
 else days_since=renew_date-prev_days; *otherwise set it to the difference;
 output;    *output the current record;
 prev_days=renew_date; *now change prev_days to the renewal date so the next record has it;
 run;
于 2013-07-03T20:12:41.770 回答