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有很多这样的问题，我已经查看了所有问题，但没有一个有正确答案，或者由于 youtube api 更改，正确答案已过时。在前往文档领域寻找最佳答案之前，我想问一下您流式传输 youtube 视频的方式是什么？我认为使用 youtube player api 并限制用户安装 Youtube 应用程序是非常可怕的方法

使用下面建议的方法，我得到“抱歉无法播放此视频”，即使我可以使用 Youtube Player Api 播放它

07-03 16:58:47.139: D/MediaPlayer(20518): getMetadata
07-03 16:58:47.139: E/MediaPlayerService(82): getMetadata failed -38
07-03 16:58:47.680: E/ARTSPConnection(82): err = 111 (Connection refused)
07-03 16:58:47.680: I/MyHandler(82): connection request completed with result -111 (Connection refused)
07-03 16:58:47.740: E/MediaPlayer(20518): error (1, -2147483648)
07-03 16:58:47.740: E/MediaPlayer(20518): Error (1,-2147483648)
07-03 16:58:47.740: D/VideoView(20518): Error: 1,-2147483648
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1 回答 1

3

新的 VideoAsyncTask().execute(); //调用在videoview中播放视频

private class VideoAsyncTask extends AsyncTask<Void, Void, Void> {
    ProgressDialog progressDialog;
    String videoUrl;

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        progressDialog = ProgressDialog.show(GallaryActivity.this, "",
                "Loading Video wait...", true);
    }

    @Override
    protected Void doInBackground(Void... params) {
        try {
            //

            String id = videosBean.getV_youtubelink(); //id of video

            String url = "http://www.youtube.com/watch?v=" + id;
            videoUrl = getUrlVideoRTSP(url);
            Log.e("Video url for playing=========>>>>>", videoUrl);
        } catch (Exception e) {
            Log.e("Login Soap Calling in Exception", e.toString());
        }
        return null;
    }

    @Override
    protected void onPostExecute(Void result) {
        super.onPostExecute(result);
        progressDialog.dismiss();
        /*
         * videoView.setVideoURI(Uri.parse(
         * "rtsp://v4.cache1.c.youtube.com/CiILENy73wIaGQk4RDShYkdS1BMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp"
         * )); videoView.setMediaController(new
         * MediaController(AlertDetail.this)); videoView.requestFocus();
         * videoView.start();
         */

        if (myvideoview.isPlaying())
            myvideoview.stopPlayback();
        myvideoview.setVideoURI(Uri.parse(videoUrl));
        MediaController mc = new MediaController(GallaryActivity.this);
        myvideoview.setMediaController(mc);
        myvideoview.requestFocus();

        myvideoview.start();
        mc.show();
    }

}

public static String getUrlVideoRTSP(String urlYoutube) {
    try {
        String gdy = "http://gdata.youtube.com/feeds/api/videos/";
        DocumentBuilder documentBuilder = DocumentBuilderFactory
                .newInstance().newDocumentBuilder();
        String id = extractYoutubeId(urlYoutube);
        URL url = new URL(gdy + id);
        HttpURLConnection connection = (HttpURLConnection) url
                .openConnection();
        Document doc = documentBuilder.parse(connection.getInputStream());
        Element el = doc.getDocumentElement();
        NodeList list = el.getElementsByTagName("media:content");// /media:content
        String cursor = urlYoutube;
        for (int i = 0; i < list.getLength(); i++) {
            Node node = list.item(i);
            if (node != null) {
                NamedNodeMap nodeMap = node.getAttributes();
                HashMap<String, String> maps = new HashMap<String, String>();
                for (int j = 0; j < nodeMap.getLength(); j++) {
                    Attr att = (Attr) nodeMap.item(j);
                    maps.put(att.getName(), att.getValue());
                }
                if (maps.containsKey("yt:format")) {
                    String f = maps.get("yt:format");
                    if (maps.containsKey("url")) {
                        cursor = maps.get("url");
                    }
                    if (f.equals("1"))
                        return cursor;
                }
            }
        }
        return cursor;
    } catch (Exception ex) {
        Log.e("Get Url Video RTSP Exception======>>", ex.toString());
    }
    return urlYoutube;

}

protected static String extractYoutubeId(String url)
        throws MalformedURLException {
    String id = null;
    try {
        String query = new URL(url).getQuery();
        if (query != null) {
            String[] param = query.split("&");
            for (String row : param) {
                String[] param1 = row.split("=");
                if (param1[0].equals("v")) {
                    id = param1[1];
                }
            }
        } else {
            if (url.contains("embed")) {
                id = url.substring(url.lastIndexOf("/") + 1);
            }
        }
    } catch (Exception ex) {
        Log.e("Exception", ex.toString());
    }
    return id;
}
于 2013-07-03T13:40:18.497 回答