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输入：7
输出：零零七，不是七

输入：17
输出：零一七，不是十七

输入：100
输出：一零零。不是一百

我希望能够像上面的示例一样进行转换，但我无法为所需的输出编写宏。我正在使用 Excel 2007。

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2 回答 2

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如果您的数字从 Row1 开始在 ColumnA 中，并且您有一个查找表（例如 D1=0、E1=0 等等，直到 D10=9 和 E10=9），那么以下可能适合： 

Sub Macro1()
    Range("B1").Select
    ActiveCell.FormulaR1C1 = _
    "=IF(LEN(RC[-1])=1,""zero zero ""&VLOOKUP(1*RC[-1],C[2]:C[3],2,0),IF(LEN(RC[-1])=2,""zero ""&VLOOKUP(1*LEFT(RC[-1],1),C[2]:C[3],2,0)&"" ""&VLOOKUP(1*RIGHT(RC[-1],1),C[2]:C[3],2,0),VLOOKUP(1*LEFT(RC[-1],1),C[2]:C[3],2,0)&"" ""&VLOOKUP(1*MID(RC[-1],2,1),C[2]:C[3],2,0)&"" ""&VLOOKUP(1*RIGHT(RC[-1],1),C[2]:C[3],2,0)))"
    ActiveCell.Copy
    Range("A1").Select
    Range(ActiveCell, ActiveCell.End(xlDown)).Offset(0, 1).Select
    ActiveSheet.Paste
End Sub
于 2013-07-03T02:45:34.287 回答
0

如果您想要纯 VBA/没有公式或查找表或帮助列等，这应该可以解决问题。基本上使用将特定整数值转换为所需字符串等效的函数来复制查找表。

Sub Test2()
    Dim rng As Range
    Dim cl As Range
    Dim clVal As String
    Dim strVal As String
    Dim i As Integer

    Set rng = Range("F1:F4")  '# Modify this line to be your range

    'Make sure they're all three digits:
    For Each cl In rng.Cells
        clVal = cl.Value
        Do While Not Len(clVal) >= 3
            clVal = "0" & clVal
        Loop
        'Now, parse the digits:
        For i = 1 To Len(clVal)
            strVal = strVal & " " & ConvertNumber(Mid(clVal, i, 1))
        Next
        strVal = Trim(strVal)
        cl.Value = strVal
        strVal = vbNullString
    Next
End Sub

Function ConvertNumber(i As Integer) As String
    Select Case i
        Case 1
            ConvertNumber = "one"
        Case 2
            ConvertNumber = "two"
        Case 3
            ConvertNumber = "three"
        Case 4
            ConvertNumber = "four"
        Case 5
            ConvertNumber = "five"
        Case 6
            ConvertNumber = "six"
        Case 7
            ConvertNumber = "seven"
        Case 8
            ConvertNumber = "eight"
        Case 9
            ConvertNumber = "nine"
        Case 0
            ConvertNumber = "zero"
    End Select
End Function

您可以很容易地将其调整为可以直接从工作表中调用的 UDF。

于 2013-07-03T03:01:26.377 回答