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我有一个具有以下重载的类：

template<typename T>
ParamContainer &operator<<(keyValue<T> &couple)
{
  insert(couple.key_, couple.value_);
  return *(this);
}

和键值

  template <typename T>
  struct keyValue
  {
    std::string key_;
    T   value_;
    keyValue(std::string key, T &value): key_(key), value_(value){}
  };

我想这样称呼我的运营商<<：

ParamContainer p;

p << ("value", "content") << ("id", 5);

所以我试图定义这个东西：

#define ParamContainer<<(X, Y) ParamContainer<<keyValue(X, Y)

或者

#define ParamContainer::operator<<(X, Y) ParamContainer<<keyValue(X, Y)

但它没有编译：

src/TemplateEngine.hpp:48:25: warning: ISO C99 requires whitespace after the macro name [enabled by default] src/ControllerPost.cpp: In member function 'virtual void ControllerPost::operator()(boost::cmatch&, http::server3::reply&, boost::container::flat_map<std::basic_string<char>, std::shared_ptr<PostParam> >&)':
src/ControllerPost.cpp:32:19: error: expected unqualified-id before '<<' token 
src/ControllerPost.cpp:32:19: error: 'X' was not declared in this scope
src/ControllerPost.cpp:32:19: note: suggested alternative:
/usr/local/include/boost/function/function_base.hpp:92:13: note: 'boost::detail::function::X'
src/ControllerPost.cpp:32:19: error: 'Y' was not declared in this scope
src/ControllerPost.cpp:32:19: error: expected ';' before 'ParamContainer'
src/ControllerPost.cpp:34:3: error: 'm' was not declared in this scope

从第 32 行开始：

  TemplateEngine::ParamContainer m;

  m << ("name", "value");

如果我不能使用 C++ 符号，我想我会找到另一种方法

4

1 回答 1

1

函数样式和常量样式预处理器定义的名称必须是有效的 C++ 标识符。它们不能包含<<符号，所以你的技巧不可能用预处理器来做。

于 2013-07-02T14:12:30.293 回答