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我想拉除 Oracle SQL 中的最后一行之外的所有行

我的数据库是这样的

Prikey - Auto_increment
common - varchar
miles - int

所以我想总结除按公共分组的主键排序的最后一行之外的所有行。这意味着对于每个不同的共同点,里程将被相加(最后一个除外)

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3 回答 3

5

注意:发布此答案后,问题已更改。前两个查询适用于原始问题。最后一个查询(在附录中)适用于更新的问题。

这应该可以解决问题,尽管对于较大的表会有点慢:

SELECT prikey, authnum FROM myTable
WHERE prikey <> (SELECT MAX(prikey) FROM myTable)
ORDER BY prikey

此查询更长,但对于大型表,它应该更快。我将由您决定:

SELECT * FROM (
  SELECT
    prikey,
    authnum,
    ROW_NUMBER() OVER (ORDER BY prikey DESC) AS RowRank
  FROM myTable)
WHERE RowRank <> 1
ORDER BY prikey

附录问题有更新;这是更新的答案。

SELECT
  common,
  SUM(miles)
FROM (
  SELECT
    common,
    miles,
    ROW_NUMBER() OVER (PARTITION BY common ORDER BY prikey DESC) AS RowRank
  FROM myTable
)
WHERE RowRank <> 1
GROUP BY common
于 2013-07-02T13:56:03.740 回答
0

查询以检索表中除第一行和最后一行之外的所有记录

select * from table_name 
where primary_id_column not in 
(
  select top 1 * from table_name order by primary_id_column asc
) 
and
primary_id_column not in 
(
  select top 1 * from table_name order by primary_id_column desc
)
于 2014-03-24T08:26:51.803 回答
0

看起来我有点太晚了,但这是我的贡献,类似于 Ed Gibbs 的第一个解决方案,但不是计算表中每个值的最大 id,然后使用内联视图进行比较。

选择 d1.prikey,
  d1.authnum
从 myTable d1,
  (SELECT MAX(prikey) prikey myTable FROM myTable) d2
哪里 d1.prikey != d2.prikey

至少我认为如果您想不使用分析,这会更有效。

于 2013-07-02T16:00:16.447 回答