python - 如何在 Python 的以下列表中转换此列表/元组？

Question

我有一个这样的列表：

x = [[(u'reads_2.fq',), (u'reads_2.fq',), (u'reads_2.fq',), (u'reads_2.fq',), (u'reads_2.fq',)]]

我想把这个列表转换成这样：

x = ['reads_2.fq', 'reads_2.fq', 'reads_2.fq', 'reads_2.fq', 'reads_2.fq']

Answer 1

使用列表推导：

>>> x = [[(u'reads_2.fq',), (u'reads_2.fq',), (u'reads_2.fq',), (u'reads_2.fq',), (u'reads_2.fq',)]]
>>> [y[0] for y in x[0]]
[u'reads_2.fq', u'reads_2.fq', u'reads_2.fq', u'reads_2.fq', u'reads_2.fq']

如果内部元组包含多个项目，则使用itertools.chain.from_iterable：

>>> from itertools import chain
>>> list(chain.from_iterable(x[0]))
[u'reads_2.fq', u'reads_2.fq', u'reads_2.fq', u'reads_2.fq', u'reads_2.fq']