0

我正在尝试在其视图中创建一个带有链接的 ListView。就像推特应用程序一样。现在这就是我正在做的事情：我在 TextView 中设置了 android:autoLink="all"。

private static class TweetViewHolder {
    public LinkifiedTextView text;
    public TextView time;
    public ImageView authorImage;
}

holder.text.setText(post.getTweet().getText());
Pattern pattern = Pattern.compile("@+[a-zA-Z_]+");
Linkify.addLinks(holder.text, pattern, "http://www.twitter.com/", null, myTransformFilter);
pattern = Pattern.compile("#+[a-zA-Z_]+");
Linkify.addLinks(holder.text, pattern, "http://www.twitter.com/", null, myTransformFilter);

TransformFilter myTransformFilter = new TransformFilter() {
@Override
public String transformUrl(Matcher match, String url) {
 return url.substring(1); //remove the $ sign
}
};

这是我的“LinkifiedTextView”代码：

@Override
public boolean onTouchEvent(MotionEvent event) {
  TextView widget = (TextView) this;
  Object text = widget.getText();
  if (text instanceof Spanned) {
      Spannable buffer = (Spannable) text;

      int action = event.getAction();

      if (action == MotionEvent.ACTION_UP
              || action == MotionEvent.ACTION_DOWN) {
          int x = (int) event.getX();
          int y = (int) event.getY();

          x -= widget.getTotalPaddingLeft();
          y -= widget.getTotalPaddingTop();

          x += widget.getScrollX();
          y += widget.getScrollY();

          Layout layout = widget.getLayout();
          int line = layout.getLineForVertical(y);
          int off = layout.getOffsetForHorizontal(line, x);

          ClickableSpan[] link = buffer.getSpans(off, off,
                  ClickableSpan.class);

          if (link.length != 0) {
              if (action == MotionEvent.ACTION_UP) {
                  link[0].onClick(widget);
              } else if (action == MotionEvent.ACTION_DOWN) {
                  Selection.setSelection(buffer,
                          buffer.getSpanStart(link[0]),
                          buffer.getSpanEnd(link[0]));

              }
              return true;
          }
      }

  }

  return false;

}

现在代码在“Spannable buffer = (Spannable) text;”上崩溃。为什么会这样，我怎样才能改变事情以使其发挥作用？谢谢！

4

1 回答 1

1

因为并非所有 Spanned 都是 Spannable。Spannable 是 Spanned 的子类，但不是唯一的子类。文本对象是其他一些子类。

于 2013-07-01T16:25:44.207 回答