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我有一个应用程序试图对 Twitter 提要进行简单的 GET 调用,但它失败并出现上述错误。在调用下面的代码之前,我能够成功获得 access_token。

string lUrl = "https://api.twitter.com/1.1/search/tweets.json&q=" + HttpUtility.UrlEncode("@typescriptlang");
var headerFormat = "Bearer {0}";
var authHeader = string.Format(
  headerFormat,
  Convert.ToBase64String(Encoding.ASCII.GetBytes(HttpUtility.UrlEncode(access_token)))
);
HttpWebRequest lRequest = HttpWebRequest.CreateHttp(lUrl);
lRequest.Method = "GET";
lRequest.Headers.Add("Authorization", authHeader);
WebResponse lResponse = lRequest.GetResponse();
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1 回答 1

0

好的,这正是您需要做的,我已经对此进行了测试,这是一个可行的解决方案:

        private string oAuthConsumerKey = ConfigurationManager.AppSettings["oAuthConsumerKey"];
        private string oAuthConsumerSecret = ConfigurationManager.AppSettings["oAuthConsumerSecret"];
        private string oAuthUrl = ConfigurationManager.AppSettings["oAuthUrl"];     
        private static string searchFormat = ConfigurationManager.AppSettings["searchFormat"];
        private string searchUrl = string.Format(searchFormat, "%23test");

        public string GetSearch()
        {
            // Do the Authenticate
            var authHeaderFormat = "Basic {0}";

            var authHeader = string.Format(authHeaderFormat,
                                           Convert.ToBase64String(
                                               Encoding.UTF8.GetBytes(Uri.EscapeDataString(oAuthConsumerKey) + ":" +

                                                                      Uri.EscapeDataString((oAuthConsumerSecret)))

                                               ));
            var postBody = "grant_type=client_credentials";
            HttpWebRequest authRequest = (HttpWebRequest)WebRequest.Create(oAuthUrl);

            authRequest.Headers.Add("Authorization", authHeader);
            authRequest.Method = "POST";
            authRequest.ContentType = "application/x-www-form-urlencoded;charset=UTF-8";
            authRequest.AutomaticDecompression = DecompressionMethods.GZip | DecompressionMethods.Deflate;
            using (Stream stream = authRequest.GetRequestStream())
            {
                byte[] content = ASCIIEncoding.ASCII.GetBytes(postBody);
                stream.Write(content, 0, content.Length);
            }
            authRequest.Headers.Add("Accept-Encoding", "gzip");
            WebResponse authResponse = authRequest.GetResponse();
            // deserialize into an object
            TwitAuthenticateResponse twitAuthResponse;
            using (authResponse)
            {
                using (var reader = new StreamReader(authResponse.GetResponseStream()))
                {
                    JavaScriptSerializer js = new JavaScriptSerializer();
                    var objectText = reader.ReadToEnd();
                    twitAuthResponse = JsonConvert.DeserializeObject<TwitAuthenticateResponse>(objectText);
                }
            }

            // Do the timeline
            HttpWebRequest timeLineRequest = (HttpWebRequest)WebRequest.Create(searchUrl);
            var timelineHeaderFormat = "{0} {1}";
            timeLineRequest.Headers.Add("Authorization",
                                        string.Format(timelineHeaderFormat, twitAuthResponse.token_type,
                                                      twitAuthResponse.access_token));
            timeLineRequest.Method = "Get";
            WebResponse timeLineResponse = timeLineRequest.GetResponse();

            var timeLineJson = string.Empty;
            using (timeLineResponse)
            {
                using (var reader = new StreamReader(timeLineResponse.GetResponseStream()))
                {
                    timeLineJson = reader.ReadToEnd();
                }
            }
            return timeLineJson;
        }

您还需要将此添加到 web 或 appsettings 中的 app.config:

<add key="searchFormat" value="https://api.twitter.com/1.1/search/tweets.json?q={0}"/>

我将在今天晚些时候更新我的 GitHub 项目以包含它:

https://github.com/andyhutch77/oAuthTwitterTimeline

将有一些代码取消注释以显示搜索。我可能不得不重新考虑项目名称,现在它也有搜索功能。

请注意,如果它不起作用,您可能会遇到 twitter 端的应用程序限制问题。我还读到有些人在共享 IP 地址上有问题。

于 2013-07-01T21:57:07.520 回答