3

我在主干中有一个应用程序，我从服务器获取数据并返回有关酒店的数据。每家酒店都可以包含许多房间（单人房、双人房、三人房……）。为此，我创建了两个 json hotel.json：

[
  {
    "id": "1", 
    "name": "Hotel1"
  }, 
  {
    "id": "2", 
    "name": "Hotel2"
  }, 
  {
    "id": "3", 
    "name": "Hotel3"
  }
]

房间.json

[
    {
      "room" : [
        {
          "id" : "r1",
          "hotel_id" : "1",
          "name" : "Singola",
        }
      ]
    },
    {
      "room" : [
        {
          "id" : "r1_1",
          "hotel_id" : "1",
          "name" : "Doppia",
        }
      ]
    },
    {
      "room" : [
        {
          "id" : "r2",
          "hotel_id" : "2",
          "name" : "Singola",
        }
      ]
    },
    {
      "room" : [
        {
          "id" : "r2_1",
          "hotel_id" : "2",
          "name" : "Tripla",
        }
      ]
    },
  ]

在 rooms.json 中有一个名为 hotel_id 的字段，用于将房间链接到其酒店。好吧，这是我在主干中查看酒店的应用程序：

var Hotel = Backbone.Model.extend({
            defaults: function() {
                return {
                    name: 'HOTEL NAME',
                    star: '5'
                }
            }
        });

        var HotelsCollection = Backbone.Collection.extend({
            model: Hotel,
            url: "includes/test-data.json",

            initialize: function(){
                console.log("Collection Hotel initialize");
            },

            parse: function(response){
                return(response);
            }     
        });

        var HotelView = Backbone.View.extend({ 
            template: _.template($("#hotel-list-template").html()),
            initialize: function(){ 
                this.collection = new HotelsCollection();
                this.collection.bind('sync', this.render, this);
                this.collection.fetch();
            },
            render: function(){
                console.log('Data hotel is fetched');
                var element = this.$el;
                element.html('');

                $(this.el).html(this.template({hotel: this.collection.models}));
            } 
        });

这是我在 udscore 中的模板：

<script type="text/template" id="hotel-list-template">
    <% _.each(hotel, function(name) { %> 
    <div id="hotel-container-<%= name.attributes.id %>">
        <p>Nome Hotel: <%= name.attributes.name %></p>
    </div>
    <% }); %>
    </script>

现在，如何将酒店内的每个房间插入到同一个 div 中？我想制作一个经典模型，一个获取数据但在渲染视图中的集合，我如何告诉骨干仅将带有 hotel_id=1 的房间插入到 id=hotel-container-1 的 div 中？

- - - - - - - - - 更新 - - - - - - - - - - -

var Hotel = Backbone.Model.extend({
            defaults: function() {
                return {
                    name: 'HOTEL NAME',
                    star: '5'
                }
            }
        });

        var HotelsCollection = Backbone.Collection.extend({
            model: Hotel,
            url: "includes/test-data.json",

            initialize: function(){
                console.log("Collection Hotel initialize");
            },

            parse: function(response){
                return(response);
            },
            getRooms : function() {
                return _.map(allRooms.where({"hotel_id" : this.get("id")}), function(room) {
                    return room.toJSON();
                });
            },
            addRoom : function(room) {
                room.set("hotel_id", this.get("id"));
                allRooms.add(room);
            },
            // this will return Backbone´s native toJSON Object
            // with an extra field "rooms" which you can access
            toJSON : function() {
                var parent = Backbone.Collection.prototype.toJSON.call(this);
                return _.extend({}, parent, {rooms : this.getRooms().toJSON()});
            }
        });

        var HotelView = Backbone.View.extend({ 
            template: _.template($("#hotel-list-template").html()),
            initialize: function(){ 
                this.collection = new HotelsCollection();
                this.collection.bind('sync', this.render, this);
                this.collection.fetch();
            },
            render: function(){
                console.log('Data hotel is fetched');
                var viewModel = this.collection.toJSON();
                this.$el.html(this.template({models:viewModel}));

            } 
        }); 


var Room = Backbone.Model.extend();
var Rooms = Backbone.Collection.extend({model:Room});

var allRooms = new Rooms();

        var hotelView = new HotelView({ 
            el: $("#hotel") 
        });
4

3 回答 3

6

我建议我们对项目架构进行一些更改。首先我们需要hotel像这样改变模型：

{
    "id": "1", 
    "name": "Hotel1",
    "rooms": []
}

其次模型和收藏：

var Room = Backbone.Model.extend();
var Rooms = Backbone.Collection.extend({
    model:Room,
    url : "rooms.json"
});
var Hotel = Backbone.Model.extend({});
var HotelCollection = Backbone.Collection.extend({
    model: Hotel,
    url: "includes/test-data.json",
    initialize: function(){
        console.log("Collection Hotel initialize");
    },

    parse: function(response) {
       response.rooms = new Rooms(response.rooms);
       return response;
    }    
});

第三视图：

    var HotelView = Backbone.View.extend({ 
        template: _.template($("#hotel-list-template").html()),
        initialize: function(){ 
            this.collection = new HotelCollection();
            this.collection.bind('sync', this.render, this);
            this.collection.fetch();
        },
        render: function(){
            console.log('Data hotel is fetched');
            bindRoomToHotel();
            var element = this.$el;
            element.html('');

            $(this.el).html(this.template({hotel: this.collection.models}));
        },

        bindRoomToHotel: function() {
            allRooms = new Rooms();
            allRooms.fetch();
            _.each(this.collection.models, function(hotel) {
                 rooms = allRooms.where({'hotel_id' : hotel.id});
                 //
                 currentHotelRooms = hotel.get('rooms');
                 currentHotelRooms.add(rooms);
                 // or You can write like 
                 // hotel.get('rooms').add(rooms);
            }
        } 
    });
    var hotelView = new HotelView({ 
        el: $("#hotel") 
    });

我想这就是全部。希望对你有帮助

于 2013-07-01T09:11:53.640 回答
2

首先，您缺少一个房间模型和一个房间集合然后，您应该在所有房间的某个地方都有一个实例。

var Room = Backbone.Model.extend();
var Rooms = Backbone.Collection.extend({
    model:Room,
    url : "rooms.json"
});

var allRooms = new Rooms();

很简单，直到这里。

不，你会为你的酒店模型创建一些方法，你会为你的房间启用一些操作

var Hotel = Backbone.Model.extend({
    getRooms : function() {
        return _.map(allRooms.where({"hotel_id" : this.get("id")}), function(room) {
            return room.toJSON();
        });
    },
    addRoom : function(room) {
        room.set("hotel_id", this.get("id"));
        allRooms.add(room);
    },
    // this will return Backbone´s native toJSON Object
    // with an extra field "rooms" which you can access
    toJSON : function() {
        var parent = Backbone.Model.prototype.toJSON.call(this);
        return _.extend({}, parent, {rooms : this.getRooms().toJSON()});
    }
});
var HotelsCollection = Backbone.Collection.extend({
    model: Hotel,
    url: "includes/test-data.json",
    initialize: function(){
        console.log("Collection Hotel initialize");
    },
    parse: function(response){
        return(response);
    }

});

这只是一个示例，您可以从中做更多的事情。

现在在你的渲染功能中......

您可以在下划线渲染方法中添加任何内容。

例如 ：

render : function() {
    //this will give you a nice formatted array (see toJSON override above)
    var viewModel = this.collection.toJSON();
    this.$el.html(this.template({models:viewModel});
}

现在，在您的视图中，您可以访问“房间”数组...

<script type="text/template" id="hotel-list-template">
    <% _.each(models, function(hotel) { %> 
    <div id="hotel-container-<%= hotel.id %>">
        <p>Nome Hotel: <%= hotel.name %></p>
        <ul>
        <% _.each(hote.rooms, function(room) { %>
            <li><%=room.name%></li>
        <% }); %>
        </ul>
    </div>
    <% }); %>
</script>
于 2013-06-30T22:47:26.417 回答
0

您可以创建一个 Room 模型，然后创建一个 Rooms 集合。然后将房间添加为 HotelView 的属性。然后调用 fetch 并使用过滤器：

    var HotelView = Backbone.View.extend({ 
        template: _.template($("#hotel-list-template").html()),
        initialize: function(){ 
            this.collection = new HotelsCollection();
            this.collection.bind('sync', this.render, this);
            this.collection.fetch();

            this.rooms = new RoomsCollection();
            this.rooms.fetch();

            var self = this;
            this.rooms = this.rooms.filter(function(room){
                      return room.get("hotel_id") === self.get("id");
                })
         },

然后你只需要将房间添加到 div 中。如果您的应用程序很复杂，您可以为房间创建视图。

这是过滤器功能的文档。

编辑：您为一个房间创建一个模板。然后在酒店模板中放置一个带有#rooms id 的空div。然后对于每个房间，您在此 div 中附加模板。

于 2013-06-30T22:26:24.370 回答