这是我的解决方案，我也测试过。
package small_Progs;
class Point {
int x, y;
Point(int x, int y) {
this.x = x;
this.y = y;
}
}
class Rectangle {
Point lt, lb, rt, rb;
Rectangle(Point lt, Point lb, Point rt, Point rb) {
this.lt = lt;
this.lb = lb;
this.rt = rt;
this.rb = rb;
}
}
public class OverlappingRectagles {
public static void main(String arg[]) {
Point lt1 = new Point(3, 8);
Point lb1 = new Point(3, 5);
Point rt1 = new Point(6, 8);
Point rb1 = new Point(6, 5);
Point lt2 = new Point(5, 6);
Point lb2 = new Point(5, 3);
Point rt2 = new Point(9, 6);
Point rb2 = new Point(9, 3);
Point lt3 = new Point(3, 7);
Point lb3 = new Point(3, 6);
Point rt3 = new Point(5, 7);
Point rb3 = new Point(5, 6);
Point lt4 = new Point(1, 2);
Point lb4 = new Point(1, 1);
Point rt4 = new Point(2, 2);
Point rb4 = new Point(2, 1);
Rectangle r1 = new Rectangle(lt1, lb1, rt1, rb1);
Rectangle r2 = new Rectangle(lt2, lb2, rt2, rb2);
Rectangle r3 = new Rectangle(lt3, lb3, rt3, rb3);
Rectangle r4 = new Rectangle(lt4, lb4, rt4, rb4);
OverlappingRectagles obj = new OverlappingRectagles();
obj.isOverLapping(r1, r2);
obj.isOverLapping(r1, r3);
obj.isOverLapping(r1, r4);
}
private void isOverLapping(Rectangle rect1, Rectangle rect2) {
Point l1 = rect1.lt;
Point l2 = rect2.lt;
Point r1 = rect1.rb;
Point r2 = rect2.rb;
if (l1.y < l2.y || l2.y < r1.y) {
System.out.println("Not Overlapping");
} else if (l1.x > r2.x || l2.x > r1.x) {
System.out.println("Not Overlapping");
} else {
if ((l1.y > r2.y && l2.y > r1.y) || (l2.y > r1.y && r2.y > r2.y)) {
System.out.println("Overlapping");
} else {
System.out.println("Not Overlapping");
}
}
}
}