17

这是我的dad

 public class Dad
    {
        public string Name
        {
            get;set;
        }
        public Dad(string name)
        {
            Name = name;
        }
    }

这是我的测试方法

public void TestDad()
        {
           UnityContainer DadContainer= new UnityContainer();
           Dad newdad = DadContainer.Resolve<Dad>();    
           newdad.Name = "chris";    
           Assert.AreEqual(newdad.Name,"chris");                 
        }

这是我得到的错误

"InvalidOperationException - the type String cannot be constructed.
 You must configure the container to supply this value"

我如何配置我DadContainer的这个断言以通过?谢谢

4

1 回答 1

28

您应该提供一个无参数的构造函数:

public class Dad
{
    public string Name { get; set; }

    public Dad()
    {
    }

    public Dad(string name)
    {
        Name = name;
    }
}

如果不能提供无参构造函数,则需要配置容器来提供,或者直接向容器注册:

UnityContainer DadContainer = new UnityContainer();
DadContainer.RegisterType<Dad>(
    new InjectionConstructor("chris"));

或通过 app/web.config 文件:

<configSections>
  <section name="unity" type="Microsoft.Practices.Unity.Configuration.UnityConfigurationSection, Microsoft.Practices.Unity.Configuration"/>
</configSections>

<unity>
  <containers>
    <container>
      <register type="System.String, MyProject">
        <constructor>
          <param name="name" value="chris" />
        </constructor>
      </register >
    </container>
  </containers>
</unity>
于 2013-06-30T14:04:44.107 回答